Answer:
copper will have more change in temperature as compare with aluminum
Explanation:
Hot piece of copper is made in contact with cold piece of aluminium
So here thermal energy transfer will take place from copper to aluminium
so by energy conservation we can say that heat given by copper is same as the heat absorbed by aluminium.
now we have

here we know that
= specific heat capacity of copper
= specific heat capacity of aluminum
given that specific heat capacity of aluminium is more than double that of copper
so we can say

so here if the mass of copper and aluminium is same then

so temperature change of copper is twice the temperature change of aluminium
So copper will have more change in temperature as compare with aluminum
Answer:
(a) I_A=1/12ML²
(b) I_B=1/3ML²
Explanation:
We know that the moment of inertia of a rod of mass M and lenght L about its center is 1/12ML².
(a) If the rod is bent exactly at its center, the distance from every point of the rod to the axis doesn't change. Since the moment of inertia depends on the distance of every mass to this axis, the moment of inertia remains the same. In other words, I_A=1/12ML².
(b) The two ends and the point where the two segments meet form an isorrectangle triangle. So the distance between the ends d can be calculated using the Pythagorean Theorem:

Next, the point where the two segments meet, the midpoint of the line connecting the two ends of the rod, and an end of the rod form another rectangle triangle, so we can calculate the distance between the two axis x using Pythagorean Theorem again:

Finally, using the Parallel Axis Theorem, we calculate I_B:

<span>A photon is characterized by either a wavelength, denoted by λ or equivalently an energy, denoted by E. There is an inverse relationship between the energy of a photon (E) and the wavelength of the light (λ) given by the equation:
E=hc/λ
E=hc/λ
where h is Planck's constant and c is the speed of light. The value of these and other commonly used constants is given in the constants page.
h = 6.626 × 10 -34 joule·s
c = 2.998 Ă— 108 m/s
By multiplying to get a single expression, hc = 1.99 Ă— 10-25 joules-m
E=hc/λ
(6.626*10^-34 J*s) x (2.998Ă—10^8m/s)/ 1.5*10^-8 m
= 1.32*10^-17 J</span>