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3 years ago

Find the y-intercept of the function 3x + 4y = 12

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

8 0

Answer:

( 0 , 3 )

Step-by-step explanation:

1. Way one of solving this problem

This equation is in standard form, one must get it to slope-intercept form to find the answer. In other words, one must solve for "y"

3x + 4y = 12

Manipulate the literal equation with inverse operations;

3x + 4y = 12

4y = 12 - 3x

/4 /4

y = - $\frac{3}{4}$ x + 4

2. Way two of solving this equation

The y-intercept is when this line intercepts the y-axis, so "x" is zero. Substitute "0" in for "x", and solve to find the y-intercept

3x + 4y = 12

x = 0

3 (0) + 4y = 12

0 + 4y = 12

Inverse operations;

4y = 12

/4 /4

y = 3

Sholpan [36]3 years ago

7 0

Answer:

y-intercept = 3

Step-by-step explanation:

3x + 4y = 12

4y = -3x + 12

4y/4 = -3/4x + 12/4

y = -3/4x + 3

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HELP!!

Step2247 [10]

That’s easy it’s 200$

8 0

2 years ago

Write the equation of the line represented by the following table

s344n2d4d5 [400]

Answer:

y = 100x + 400

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 400) and (x₂, y₂ ) = (1, 500) ← 2 points from the table

m = $\frac{500-400}{1-0}$ = 100

note the line crosses the y- axis at (0, 400) ⇒ c = 400

y = 100x + 400 ← equation of line

4 0

3 years ago

What is the slope of a line perpendicular to the line whose equation is x−2y=12.

seraphim [82]

Answer:

-2/x

Step-by-step explanation:

simplified is y = -x/2 - 6

Perpendicular slopes are just reciprocals of the original slope, so just flipp the original slope around to be the complete opposite.

Example if slope= -2, the reciprocal= -1/2

Just flip the numerator with the denominator for perpendicular slope

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2 years ago

Without multiplying, determine the sign of the product (−247,634)(183,758).

adoni [48]

Negative bc negative times positive is negative

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3 years ago

HELP ASAP

Andrei [34K]

Answer:

$radius = \sqrt{13}$ or $radius = 3.61$

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

$Center = (x,0)$

Next is to determine the value of x through the formula of radius;

$radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}$

Considering the given points

$A(x_1,y_1) = A(-3,2)$

$B(x_2,y_2) = B(-2,3)$

$Center(x,y) =Center (x,0)$

Substitute values for $x,y,x_1,y_1,x_2,y_2$ in the above formula

We have:

$\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}$

Evaluate the brackets

$\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}$

$\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}$

Eva;uate all squares

$\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}$

$\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}$

Take square of both sides

$(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9$

Evaluate the brackets

$3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9$

$9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9$

$9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9$

Collect Like Terms

$6x -4x + x^2 -x^2 = 4 -4 + 9 - 9$

$2x = 0$

Divide both sides by 2

$x = 0$

This implies the the center of the circle is

$Center = (x,0)$

Substitute 0 for x

$Center = (0,0)$

Substitute 0 for x and y in any of the radius formula

$radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}$

$radius = \sqrt{(x_1)^2 + (y_1)^2}$

Considering that we used x1 and y1;

In this case we have that; $A(x_1,y_1) = A(-3,2)$

Substitute -3 for x1 and 2 for y1

$radius = \sqrt{(-3)^2 + (2)^2}$

$radius = \sqrt{13}$

$radius = 3.61$ ---<em>Approximated</em>

7 0

3 years ago

Find the ​y​-intercept​ of the function 3​x​ + 4​y​ = 12

Find the y-intercept of the function 3x + 4y = 12