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Amanda [17]
3 years ago
8

Find the ​y​-intercept​ of the function 3​x​ + 4​y​ = 12

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
8 0

Answer:

( 0 , 3 )

Step-by-step explanation:

1. Way one of solving this problem

This equation is in standard form, one must get it to slope-intercept form to find the answer. In other words, one must solve for "y"

3x + 4y = 12

Manipulate the literal equation with inverse operations;

3x + 4y = 12

4y = 12 - 3x

/4      /4

y = - \frac{3}{4}x + 4

2. Way two of solving this equation

The y-intercept is when this line intercepts the y-axis, so "x" is zero. Substitute "0" in for "x", and solve to find the y-intercept

3x + 4y = 12

x = 0

3 (0) + 4y = 12

0 + 4y = 12

Inverse operations;

4y = 12

/4   /4

y = 3

Sholpan [36]3 years ago
7 0

Answer:

y-intercept = 3

Step-by-step explanation:

3x + 4y = 12

4y = -3x + 12

4y/4 = -3/4x + 12/4

y = -3/4x + 3

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A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the
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Answer:

The area is growing at a rate of \frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 \frac{cm}{min} and we identify such as the following differential rate:

\frac{dr}{dt} = 3\,\frac{cm}{min}

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find  \frac{dA}{dt}.

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

A=\pi\,r^2

We now apply the derivative operator with respect to time (\frac{d}{dt}) to this equation, and use chain rule as we find the quadratic form of the radius:

\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}

Now we replace the known values of the rate at which the radius is growing ( \frac{dr}{dt} = 3\,\frac{cm}{min}), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\

which we can round to one decimal place as:

\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}

4 0
3 years ago
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