Given:
Line P Q has points (-5, 3) and (5, 1).
Line R S has points (-4, -2) and (0, -4).
To find:
The relationship between lines PQ and RS.
Solution:
If a line passing through two points, then the slope of line is
![m=\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
Line P Q has points (-5, 3) and (5, 1). So, slope of line PQ is
![m_1=\dfrac{1-3}{5-(-5)}](https://tex.z-dn.net/?f=m_1%3D%5Cdfrac%7B1-3%7D%7B5-%28-5%29%7D)
![m_1=\dfrac{-2}{5+5}](https://tex.z-dn.net/?f=m_1%3D%5Cdfrac%7B-2%7D%7B5%2B5%7D)
![m_1=\dfrac{-2}{10}](https://tex.z-dn.net/?f=m_1%3D%5Cdfrac%7B-2%7D%7B10%7D)
![m_1=\dfrac{-1}{5}](https://tex.z-dn.net/?f=m_1%3D%5Cdfrac%7B-1%7D%7B5%7D)
Line R S has points (-4, -2) and (0, -4). So, slope of line RS is
![m_2=\dfrac{-4-(-2)}{0-(-4)}](https://tex.z-dn.net/?f=m_2%3D%5Cdfrac%7B-4-%28-2%29%7D%7B0-%28-4%29%7D)
![m_2=\dfrac{-4+2}{0+4}](https://tex.z-dn.net/?f=m_2%3D%5Cdfrac%7B-4%2B2%7D%7B0%2B4%7D)
![m_2=\dfrac{-2}{4}](https://tex.z-dn.net/?f=m_2%3D%5Cdfrac%7B-2%7D%7B4%7D)
![m_2=\dfrac{-1}{2}](https://tex.z-dn.net/?f=m_2%3D%5Cdfrac%7B-1%7D%7B2%7D)
Slopes of two parallel lines are equal.
![m_1\neq m_2](https://tex.z-dn.net/?f=m_1%5Cneq%20m_2)
They are not parallel because their slopes are not equal.
Therefore, the correct option is C.