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anastassius [24]

3 years ago

11

A girl throws a paper airplane from her treehouse. The height of the plane is a function of time and can be modeled by the equat

ion ℎ()=25+2.5−122. Height is measured in feet and time is measured in seconds.

1 answer:

wel3 years ago

3 0

How do u make a paper airplane

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Evaluate the following expression:<br> 5+7(3x+y) when x=12, y=8

timofeeve [1]

First step is 5+7(36x+8y) because you have to distribute

5 0

3 years ago

Read 2 more answers

A line passes through the point (5,-11) and has a slope of -2 Find an equation of this line.

Vsevolod [243]

Formula: y = mx + b

m being the slope

Slope given: -2, plug it in

Y = -2x + b

Now find y intercept (b)

Plug in the point (5,-11)

-11 = -2(5) + b

-11 = -10 + b, b = -1

Solution: y = -2x -1

5 0

3 years ago

Can anybody help me please

GREYUIT [131]

Question 7: Option 1: x = 33.5°

Question 8: Option 3: x = 14.0°

Step-by-step explanation:

<u>Question 7:</u>

In the given figure, the value of perpendicular and hypotenuse is given, so we have to use any trigonometric ratio to find the value of angle as the given triangle is a right-angled triangle

So,

Perpendicular = P = 32

Hypotenuse = H = 58

So,

$sin\ x = \frac{P}{H}\\sin\ x = \frac{32}{58}\\sin\ x = 0.5517\\x = sin^{-1} ( 0.5517)\\x =33.48$

Rounding off to nearest tenth

x = 33.5°

<u>Question 8:</u>

In the given figure, the value of Base and Perpendicular is given, we will use tangent trigonometric ratio to find the value of x

So,

Perpendicular = P = 5

Base = B = 20

So,

$tan\ x = \frac{P}{B}\\tan\ x = \frac{5}{20}\\tan\ x = 0.25\\x = tan^{-1} (0.25)\\x = 14.036$

Rounding off to nearest tenth

x = 14.0°

Keywords: Right-angled triangle, trigonometric ratios

Learn more about trigonometric ratios at:

#LearnwithBrainly

8 0

3 years ago

Someone please help me

bearhunter [10]

B. triangle and triangular prism

6 0

3 years ago

Solve each of the following equations using a method other than the Quadratic Formula.

liraira [26]

Answer:

A)

y^2-6y = 0

or, y(y-6) = 0

or, y = 0 or y = 6

B)

n^2+5n+7 = 7

or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)

or, n^2+5n = 0

or, n(n+5) = 0

or, n=0 or n= -5

C)

2t^2-14t+3 = 3

or, 2t^2-14t = 0

or, 2t(t-7) = 0

or, t=0 or t=7

D)

1/3x^2+3x-4 = -4

or, 1/3x^2+3x = 0

or, 1/3x(x+9) = 0

or, x=0 or x= -9

E)

Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.

THANK YOU FOR READING.

8 0

2 years ago