That look hard what subject is it
Answer:
It is not correct, the answer is 15
Step-by-step explanation:
They forgot the rule of PEMDAS, and accidentally subtracted before they multiplied. It should've gone
(25+3) - 7 x 3 + (2x4)
28-7x3+8
28-21+8
Since it's minus 21, that means it's negative, so -21+8=13
28-13=15
Answer:
acute
Step-by-step explanation:
Ya but I think its like 40 hope this helps
The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417