All categories

3 years ago

2tan(45-A)/1+tan^2(45-A)=cos2a

Mathematics

1 answer:

AVprozaik [17]3 years ago

3 0

Answer:

Let θ = (45 - A)°.

=> 2Tanθ/ 1 + Tan²θ

=> 2Sinθ/Cosθ / 1 + Sin²θ / Cos²θ

=> 2Sinθ/Cosθ/ Cos²θ + Cos²θ / Cos²θ

=> 2Sinθ/Cosθ/ 1 / Cos²θ

=> 2SinθCos²θ/Cosθ

=> 2SinθCosθ

=> Sin2θ

But we assumed θ = (45 - A)°,

=> Sin2(45 - A)

=> Sin(90 - 2A) (∵ Sin(90 - θ) = Cosθ)

=> Cos2A

= R.H.S

Hence proved.

Step-by-step explanation:

You might be interested in

40 POINTS !! 40 POINTS !!<br><br> PLEASE HELP , DONT SKIP !<br><br> NO LINKS OR FILES.

zloy xaker [14]

Answer:

Just click an x on the graph for each number in the chart.

1/4 would have 4 x's

2/4 would have 2 x's

3/4 would have 1 x

1 would have 2 x's

5 0

3 years ago

What is wrong with the equation? 2 x−3 dx = x−2 −2 2 −3 = − 5 72 −3 f(x) = x−3 is continuous on the interval [−3, 2] so FTC2 can

Wewaii [24]

Answer:

Hello your question is incomplete below is the complete question

What is wrong with the equation? integral^2 _3 x^-3 dx = x^-2/-2]^2 _3 = -5/72 f(x) = x^-3 is continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous at x = -3, so FTC2 cannot be applied The lower limit is less than 0, so FTC2 cannot be applied. There is nothing wrong with the equation. If f(2) = 14, f' is continuous, and f'(x) dx = 15, what is the value of f(7)? F(7) =

answer : The value of f(7) = 29

Step-by-step explanation:

Attached below is the detailed solution

Hence : F(7) - 14 = 15

F(7) = 15 + 14 = 29

8 0

4 years ago

Multiply the following binomials; note that every binomial given in the problems below is a polynomial in one variable,

MrMuchimi

Answer:

In step-by-step-explanation

Step-by-step explanation:

2) ( x + 1 ) * ( x - 7 ) = x² - 7x + x - 7 ⇒ x² - 6x - 7

In x² - 6x - 7 a = 1 b = -6 c = -7

3) ( x + 9 ) * ( x + 2 ) = x² + 2x + 9x + 18 ⇒ x² + 11x + 18

In x² + 11x + 18 a = 1 b = 11 c = 18

4) ( x - 5 ) * ( x - 3 ) = x² - 3x - 5x + 15 ⇒ x² - 8x + 15

In x² - 8x + 15 a = 1 b = -8 c = 15

5) ( x + 15 ) * 2 * ( x - 1 ) ⇒ ( x + 15 ) * ( 2x - 2 ) ⇒ 2x² -2x + 30x - 30

2x² + 28x - 30 a = 2 ² b = 28 c = 30

6) ( x - 5 ) * ( 4x - 3 ) ⇒ 4x² - 3x - 20x + 15

In 4x² - 3x - 20x + 15 ⇒ a = 4 b = -20 c = 15

6 0

3 years ago

Please help it's the last question on my homework

Nostrana [21]

Answer:

<h3>The vertical value in a pair of coordinates. How far up or down the point is. The Y Coordinate is always written second in an ordered pair of coordinates (x,y) such as (12,5). In this example, the value "5" is the Y Coordinate. Also called "Ordinate"</h3>

7 0

3 years ago

370 people bought tickets to a fair. Adult tickets were $7 and kids tickets were $3. Total revenue was $1750. Child tickets are

galina1969 [7]

210 children tickets are sold

<em><u>Solution:</u></em>

Let "x" be the number of child tickets sold

Let "y" be the number of adult tickets sold

Cost of 1 adult ticket = $ 7

Cost of 1 child ticket = $ 3

<em><u>Given that 370 people bought tickets to a fair</u></em>

number of child tickets sold + number of adult tickets sold = 370

x + y = 370 ------ eqn 1

<em><u>Total revenue was $1750. Therefore,</u></em>

number of child tickets sold x Cost of 1 child ticket + number of adult tickets sold x Cost of 1 child ticket = 1750

$x \times 3 + y \times 7 = 1750$

3x + 7y = 1750 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

x = 370 - y ------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

3(370 - y) + 7y = 1750

1110 - 3y + 7y = 1750

4y = 1750 - 1110

4y = 640

From eqn 3,

x = 370 - 160

Thus 210 children tickets are sold

7 0

3 years ago