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Black_prince [1.1K]
2 years ago
15

What is the value of x?

Mathematics
2 answers:
olga2289 [7]2 years ago
6 0

Answer:

it's and isoceles triangle so the base angles will be the same.

28 + 28 + 9 = 65

180-65=115

5x = 115

115/5 =23

23 X 5 + 9 = 124 degrees

Anna11 [10]2 years ago
3 0

Answer:

x=23

Step-by-step explanation:

The first triangle has two sides that are the same, therefore the two bottom angles are the same as well, so the two bottom angles equal to 56 degrees of the total 180 degrees that a triangle should have. That leaves the last angle to be 124 degrees.

Now what you do is subtract 9 from 124 to get 115

Lastly divide 115 by 5 to get 23.

:)

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The value of the solid's surface area is equal to the value of the solid's volume. Find the value of x. We know the length is 9
Lerok [7]

Given:

The value of the solid's surface area is equal to the value of the solid's volume.

Length(l) = 9 units

width(b) = 4 units

Height(h) = x units

To find:

The value of x.

Solution:

Solid's surface area is

Area=2(lb+bh+hl)

Area=2(9\times 4+4\times x+x\times 9)

Area=2(36+4x+9x)

Area=2(36+13x)

Area=72+26x

Volume of solid is

Volume=l\times b\times h

Volume=9\times 4\times x

Volume=36x

Solid's surface area = Volume of solid

72+26x=36x

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Divide both sides by 10.

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Therefore, the value of x is 7.2.

4 0
3 years ago
Seven over nine<br> to the power of<br> two
anyanavicka [17]

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Step-by-step explanation:

3 0
3 years ago
Help and explain explain !!!!!!!!!!
tigry1 [53]

Answer:

x=-1\text{ or }x=11

Step-by-step explanation:

For a=|b|, we have two cases:

\begin{cases}a=b,\\a=-b\end{cases}

Therefore, for 18=|15-3x|, we have the following cases:

\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}

Solving, we have:

\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}.

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\implies \boxed{x=-1\text{ or }x=11}

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2 years ago
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Step-by-step explanation:

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2 years ago
What is the angle of BTC, Angle TBC,Angle TCB
Goryan [66]

By geometric and algebraic properties the angles BTC, TBC and TBC from the triangle BTC are 128°, 26° and 26°, respectively.

<h3>How to determine the angles of a triangle inscribed in a circle</h3>

According to the figure, the triangle BTC is inscribed in the circle by two points (B, C). In this question we must make use of concepts of diameter and triangles to determine all missing angles.

Since AT and BT represent the radii of the circle, then the triangle ABT is an <em>isosceles</em> triangle. By geometry we know that the sum of <em>internal</em> angles of a triangle equals 180°. Hence, the measure of the angles A and B is 64°.

The angles ATB and BTC are <em>supplmentary</em> and therefore the measure of the latter is 128°. The triangle BTC is also an <em>isosceles</em> triangle and the measure of angles TBC and TCB is 26°.

By geometric and algebraic properties the angles BTC, TBC and TBC from the triangle BTC are 128°, 26° and 26°, respectively.

To learn more on triangles, we kindly invite to check this verified question: brainly.com/question/2773823

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