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Taya2010 [7]
3 years ago
8

A wire carries a current of 6.52 A in a direction that makes an angle of 44.8 degrees with the direction of a magnetic field of

strength 0.258 T. What is the magnetic force on a 3.61 m length of wire
Physics
1 answer:
Komok [63]3 years ago
4 0

Answer:

F=4.27N

Explanation:

From the question we are told that:

Current  I = 6.52 A

Angle \theta= 44.8 \textdegree

Magnetic field   B= 0.258 T.

Length l=3.61m

Generally the equation for  Magnetic force F is mathematically given by

 F=BIlsin\theta

Therefore

 F=0.258*6.52*3.61*sin 44.8

 F=4.27N

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Answer:

a=0   v = v₀ + a t

a=0    line is horizontal

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6 0
3 years ago
An electron emitted in the beta decay of bismuth-210 has a mean kinetic energy of 390 keV. (a) Find the de Broglie wavelength of
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Explanation:

Given that,

The mean kinetic energy of the emitted electron, E=390\ keV=390\times 10^3\ eV

(a) The relation between the kinetic energy and the De Broglie wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2meE}}

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(b) According to Bragg's law,

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Answer:

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