Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.
<h3>
Work done</h3>
Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;
W = F × d
Where F is force applied or Weight and d is distance
Also Force = Weight = mass × acceleration due to gravity.
Since gravity is acting on the boxes as it been lift
W = Weight × height from ground level
W = mg × d
Where m is mass of the boxes, g is accelration due to gravity( g = 9.8m/s² ) and d is distance from ground level.
Given the data in the question;
- Since each box has a mass of 7.89 kg
- Mass of the 345 boxes = 345 × 7.89 kg = 2722.05kg
- Distance or height d = 6.0m
To determine the work done, we substitute our values into the expression above.
W = mg × d
W = 2722.05kg × 9.8m/s² × 6.0m
W = 160056.5kgm²/s²
W = 160056.5J
W = 1.6 × 10⁵J
Therefore, Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.
Learn more about work done here: brainly.com/question/26115962
Answer:
1.758820×10^11(-2.5i-0.8j) m/s^2
Explanation:
From the question, the parameters given are; E=(2.80i+ 5.20j) v/m, a uniform magnetic field,B= 0.400K T, acceleration, a= ??? and velocity vector, v= 11.0i metre per seconds (m/s)...
We can solve this problem using the formula below;
Ma= q[E+V × B] ---------------(1).
Note: q is negative, m= mass of electron.
Making acceleration,a the subject of the formula and substituting the parameters into equation (1);
a= -e/m × (2.5i + 5.2j +11.0i × 0.400K)
a= -e/m × (2.5i+5.2j-4.4j)
a= e/m × (-2.5i - 0.8j)
e/m= 1.758820×10^11 c/kg
Therefore, slotting in the value of charge to mass(e/m) ratio;
a= 1.7588×10^11×(-2.5i-0.8j) m/s^2
Answer:
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Force = mass * acceleration = 1500kg * 8m/s²
