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fredd [130]
3 years ago
13

What is the exact meaning of croos section and cross sectional area of a conductor?

Physics
1 answer:
Sonbull [250]3 years ago
4 0
The cross section is the little tiny circle you see when you cut a wire
and look at the flat, cut end.

The cross-sectional area of the wire is the area of that little circle. 
It's equal to

                           Area = (pi) x (1/4) x (Diameter of the wire)²
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A ball at the top of a hill is an example of ______ and a ball rolling down the hill is an example of ______.
larisa [96]

Potential energy , Kinetic energy

<h3 /><h3>What is kinetic energy and potential energy?</h3>

Kinetic energy is a form of energy that posses by an object due to its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.

Potential energy is the energy held by an object due to its position relative to other objects, stresses within itself, its electric charge, or other factors.

According to given condition,

At first,

When a ball is at the top of a hill , it posses a potential energy because the ball is at some height from the surface  where  the energy held by ball is due to its position.

That is why,  a ball at the top of a hill is an example of Potential energy.

Secondly,

When a ball is rolling down the hill , it posses kinetic energy because the ball have some energy that posses by an object due to its motion.

That is why, a ball rolling down the hill is an example of  Kinetic energy.

Learn more about Potential energy and Kinetic energy here:

brainly.com/question/11749818

#SPJ1

6 0
2 years ago
A 2.4-kg cart is rolling along a frictionless, horizontal track towards a 1.7-kg cart that is held initially at rest. The carts
inessss [21]

Answer:

Explanation:

Mass of first cart M1=2.4kg

Velocity of first cart U1=4.1m/s

Mass of second cart M2=1.7kg

Second cart is initially at rest U2=0

After an instant, the velocity of the second cart is U2=-2.8m/s

Now after collision the two cart move together with the same velocity I.e inelastic collision

Using conservation of momentum

Momentum before collision, = momentum after collision

M1U1 + M2U2 = (M1+M2)V

2.4×4.1 + 1.7× -2.8 =(2.4+1.7)V

9.84 - 4.76 = 4.1V

5.08=4.1V

V=5.08/4.1

V=1.24m/s

The momentum of the two cart at that instant is

M1U1+M2U2

2.4×4.1 + 1.7× -2.8

9.84 - 4.76

5.08kgm/s

So the momentum at the instant the velocity is 4.1m/s for cart 1 and -2.8m/s for cart 2 is 5.08kgm/s

3 0
3 years ago
Must physics always be explained by math?
cluponka [151]

Answer:

Because Physics is mainly composited of math

Explanation:

If you really think about it the only way any science works is off maths, whether that be measuring the amount of NaOH to put into a solution or determening the amount of sugar you want in a cake it all relys on maths

5 0
3 years ago
What is the potential energy of a one kilogram box of chocolates hidden on a
sveta [45]

Answer:

um it well it will be 19.6 d) 9.8 J

Explanation:

7 0
3 years ago
Read 2 more answers
A ladder of length 10 is leaning against a wall. The vertical wall is frictionless while the horizontal surface is rough. The an
bogdanovich [222]

Answer:

105.1N

Explanation:

According to the newton second law

\sum F_x = ma_x\\F_m - F_f = ma_x\\

Since the acceleration is zero, then;

F_m - F_f = 0\\Fm = F_f\\

Since;

F_m = mg sin \theta, \  hence \ F_f = mg sin \theta

Given the following

mass of ladder m = 14kg

acceleration due to gravity g = 9.8m/s²

θ = 50°

Substitute

F_f = 14(9.8)sin50\\F_f = 14(7.5072)\\F_f = 105.1N\\

Hence the magnitude of the friction force (in N) exerted on the ladder in the point of contact with the horizontal surface is 105.1N

8 0
3 years ago
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