$\bf \begin{array}{ccll}
lbs&kgs\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
2.2&1\\
3.18&k
\end{array}\implies \cfrac{2.2}{3.18}=\cfrac{1}{k}\implies k=\cfrac{3.18\cdot 1}{2.2}$

3 0

3 years ago

If f(x) = 3x - 9 and g(x) = x², what is (gºf)(5)?

Xelga [282]

Answer:

Step-by-step explanation:

Here, f(x) is the input to g(x), forming a composite function.

To evaluate (gºf)(5),

1) find the value of f(5). It is f(5) = 6.

2) Use this result as the input to g(x): g(6) = (6)^2 = 36

3 0

3 years ago

Rationalize the denominator 2√7+√3/3√7-√3

Dahasolnce [82]

Answer:

$\frac{2 \sqrt{7} + \sqrt{3}}{3 \sqrt{7} - \sqrt{3} } = \frac{2 \sqrt{7} + \sqrt{3}}{3 \sqrt{7} - \sqrt{3} } . \frac{3 \sqrt{7} + \sqrt{3} }{3 \sqrt{7} + \sqrt{3} } \\ \\ = \frac{(2 \sqrt{7} + 3)(3 \sqrt{7} + \sqrt{3}) }{(3 \sqrt{7} - 3)(3 \sqrt{7} + \sqrt{3} ) } \\ \\ = \frac{(42 + 2 \sqrt{21} + 9 \sqrt{21} + 3 \sqrt{21} )}{63 - 3} \\ \\ = \frac{42 + 2\sqrt{21} + 9 \sqrt{21} + 3 \sqrt{21} }{60}$

5 0

3 years ago

Read 2 more answers