12(2+7)
12 is the GCF for 24 with 12 x2 =24 and 12 is the GCF for 84 with 12 x7= 84.
Answer:
500/6 min if I'm correct
Step-by-step explanation:
Answer:
[2] x = -5y - 4
// Plug this in for variable x in equation [1]
[1] 2•(-5y-4) - 5y = 22
[1] - 15y = 30
// Solve equation [1] for the variable y
[1] 15y = - 30
[1] y = - 2
// By now we know this much :
x = -5y-4
y = -2
// Use the y value to solve for x
x = -5(-2)-4 = 6
Solution :
{x,y} = {6,-2}
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Terms and Topics
Linear Equations with Two Unknowns
Solving Linear Equations by Substitution
Related Links
Algebra - Linear Systems with Two Variables
Step-by-step explanation:
Answer:
slope is about 1.67
Step-by-step explanation:
2/1.2 ≈ 1.67
hope this helps :)
Answer:
Max Value: x = 400
General Formulas and Concepts:
<u>Algebra I</u>
- Domain is the set of x-values that can be inputted into function f(x)
<u>Calculus</u>
- Antiderivatives
- Integral Property:

- Integration Method: U-Substitution
- [Integration] Reverse Power Rule:

Step-by-step explanation:
<u>Step 1: Define</u>

<u>Step 2: Identify Variables</u>
<em>Using U-Substitution, we set variables in order to integrate.</em>

<u>Step 3: Integrate</u>
- Define:

- Substitute:

- [Integral] Int Property:

- [Integral] U-Sub:

- [Integral] Rewrite:

- [Integral - Evaluate] Reverse Power Rule:

- Simplify:

- Back-Substitute:

- Factor:

<u>Step 4: Identify Domain</u>
We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.
Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.