Answer:
Maximum area = 800 square feet.
Step-by-step explanation:
In the figure attached,
Rectangle is showing width = x ft and the side towards garage is not to be fenced.
Length of the fence has been given as 80 ft.
Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced
80 = x + x + y
80 = 2x + y
y = (80 - 2x)
Now area of the rectangle A = xy
Or function that represents the area of the rectangle is,
A(x) = x(80 - 2x)
A(x) = 80x - 2x²
To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.
= 80 - 4x
A'(x) = 80 - 4x = 0
4x = 80
x = 
x = 20
Therefore, for x = 20 ft area of the rectangular patio will be maximum.
A(20) = 80×(20) - 2×(20)²
= 1600 - 800
= 800 square feet
Maximum area of the patio is 800 square feet.
Answer:
None
Step-by-step explanation:
By using the equation a^2 +b^2=c^2 we can see if it will work.
Substitute a for 6 and b for 2 to get 6^2+2^2=40
when you 
you don't get 7 therefore you cant make any triangles
Answer:
Step-by-step explanation:
Answer:
6a) 1
6b) 11
7a) 4
7b) 10
8a) 6
8b) 14
9a) 11
9b) 13
Step-by-step explanation:
In order to make a triangle, we need to follow this property:
a <= b + c
(Known as "triangle inequality")
Where 'a' is the bigger side and 'b' and 'c' are the other two sides.
So, using this property, we can solve the following problems:
6a) Maximum side will be 6:
6 <= 5 + c
c = 1
6b) Minimum sides will be 5 and 6:
a <= 5 + 6
a = 11
7a) Maximum side will be 7:
7 <= 3 + c
c = 4
7b) Minimum sides will be 3 and 7:
a <= 3 + 7
a = 10
8a) Maximum side will be 10:
10 <= 4 + c
c = 6
8b) Minimum sides will be 4 and 10:
a <= 4 + 10
a = 14
9a) Maximum side will be 12:
12 <= 1 + c
c = 11
9b) Minimum sides will be 1 and 12:
a <= 1 + 12
a = 13
