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2 years ago

A cube with sides that are 2 cm has a mass of 48 g and its density would be ___________ g/cm3.

Mathematics

2 answers:

Bogdan [553]2 years ago

7 0

Answer:

p = <u>6</u> g/cm³

Step-by-step explanation:

Given: cube sides= 2 cm and 48 g

To find: The cube's density

Formula: ${p} \frac{m}{V}$

Solution: Measure the height, width, and depth of the shipment in inches.

Multiply the three measurements (height x width x depth).

Divide the total cubic inches by 1,728 (the number of cubic inches in a cubic foot).

Divide the weight (in pounds) of the shipment by the total cubic feet.

p = density

m = mass

V = volume

erica [24]2 years ago

5 0

Answer:

6g/cm^3

Step-by-step explanation:

The density of the cube would be 6 grams/cm^3. I got this answer by first finding the volume of the cube, 2^3 which gives me 8 cm as the initial volume of the cube. Then, the 48 grams of mass the cube has allows me to divide 48 / 8 which gave me 6. And 6 would be the density of the cube in grams.

Answer: 6g/cm^3

Hope this helps!

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timama [110]

Hello!

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2 years ago

Part C: Find the distance from B to E and from P to E. Show your work. (4 points)

garri49 [273]

Answer:

BE = 294.23 ft

PE = 259.62 ft

Step-by-step explanation:

Quadrilateral CPRG is a parallelogram.

CP || GR

In triangles BCG and BPE

$\angle BCG \cong \angle BPE (Alternate \: \angle 's) \\\angle GBC \cong \angle EBP (Vertical \: \angle 's) \\\therefore \triangle BCG \sim \triangle BPE (AA \: postulate) \\\\\therefore \frac{BE}{BG} =\frac{PE}{GC} =\frac{BP}{BC}...(csst)\\\\\therefore \frac{BE}{425} =\frac{PE}{375} =\frac{225}{325}\\\\\therefore \frac{BE}{425} =\frac{PE}{375} =\frac{9}{13}\\\\\therefore \frac{BE}{425} =\frac{9}{13}\\\\BE =\frac{9\times 425}{13}\\\\BE =\frac{3,825}{13}\\\\BE = 294.23\: ft \\\\\&\\\frac{PE}{375} =\frac{9}{13}\\\\PE =\frac{9\times 325}{13}\\\\PE =\frac{3,375}{13}\\\\PE = 259.615385 \\\\PE = 259.62 \: ft\\\\$