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sattari [20]
3 years ago
11

How to solve this trig triangle

Mathematics
2 answers:
fiasKO [112]3 years ago
7 0

Step-by-step explanation:

First you need to find the semi perimeter (s) and apply the formula of the triangle and you will get your answer

vitfil [10]3 years ago
4 0
Use the law of cosines:

c2=a2+b2−2ab cosC
The law of cosines is used in SSS and SAS triangles, and the law of sines in ASA, and the ambiguous case of SSA (which you have to solve two triangles).

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(6+√25)/(4-√3) can be written in the form of (2+s√3)/13 where r and s are both integers what are the values of r and s
cestrela7 [59]

Answer:

r = 33

s = 18

Step-by-step explanation:

Given expression is \frac{6+\sqrt{27}}{4-\sqrt{3}}.

Multiply numerator and denominator with the conjugate of (4 - √3).  

\frac{(6+\sqrt{27})(4+\sqrt{3})}{(4-\sqrt{3})(4+\sqrt{3})}

= \frac{4(6+\sqrt{27})+\sqrt{3}(6+\sqrt{27})}{4^{2}-(\sqrt{3})^2}

= \frac{24+4\sqrt{27}+6\sqrt{3}+\sqrt{81})}{16-3}

= \frac{24+12\sqrt{3}+6\sqrt{3}+\sqrt{81})}{16-3}

= \frac{24+18\sqrt{3}+9}{13}

= \frac{33+18\sqrt{3}}{13}

Now compare this expression with \frac{r+s\sqrt{3} }{13}

r = 33

s = 18

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Answer:

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If a baker doubles a recipe that calls for 6-2/3 cups of flour. How many cups will be needed in all?
nadya68 [22]
Hey there!

The easiest way I could think to do this is by converting your mixed number to an improper fraction and multiplying the fraction by 2, or 2 over 1. 

6 \frac{2}{3}  = 6*3+2 =  \frac{20}{3}

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Since you can't simplify this fraction in its improper form, just convert it back into a mixed number. 

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Hope this helped you out! :-)
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