Question

Jill has a swimming pool in her backyard. It is shaped like a rectangle and measures approximately 16.3 feet wide and 26.2 feet long. It is an average of 5 feet deep. During a few hot weeks during the summer, some water evaporates from the pool, and Jill needs to add 8 inches of water to the depth of the pool, using her garden hose. Although her water pressure varies, the water flows through Jill’s garden hose at an average rate of 10 gallons/minute.
How many liters will Jill need to add to her pool to return the water level to its original depth? How many gallons of water is this? Reminder: Volume = Length x Width x Depth

Answer 1

Answer:

The dimensions of swimming pool are:

Length = 26.2 feet

Width = 16.3 feet

Height = 5 feet

During a few hot weeks during the summer, some water evaporates from the pool, and Jill needs to add 8 inches of water to the depth of the pool.

We will convert 8 inches o feet.

1 inch = 1/12 feet

So, 8 inch = $8/12=0.66$ feet

Now we have to tell how much water will be there in 0.66 feet depth.

So, volume = $16.3\times26.2\times0.66=281.86$ cubic feet.

1 cubic feet has 7.480 gallons

So, 281.86 cubic feet will have $281.86\times7.480=2108.31$ gallons of water.