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Mrrafil [7]
3 years ago
11

13. Find the equations of the straight lines which passes

Mathematics
1 answer:
ipn [44]3 years ago
3 0

9514 1404 393

Answer:

  • y = 1/2x +2
  • y = -2x +7

Step-by-step explanation:

The slope of a line is the tangent of the angle it makes with the x-axis. The given line has a slope of -1/3, so the lines we want will have slopes of ...

  m1 = tan(arctan(-1/3) +45°) = 0.5 . . . . . using a calculator

  m2 = tan(arctan(-1/3) -45°) = -2

Of course, these two lines are perpendicular to each other, so their slopes will have a product of -1: (0.5)(-2) = -1.

__

We can use the point-slope form of the equation for a line to write the desired equations:

  y = m(x -h) +k . . . . . line with slope m through point (h, k)

<u>Line 1</u>:

  y = 1/2(x -2) +3

  y = 1/2x +2

<u>Line 2</u>:

  y = -2(x -2) +3

  y = -2x +7

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question 1. Solve the equation 8-7/10 c = 6 - 1/5c for c

8 - 7/10c = 6 - 1/5c

subtract 8 from both sides:

8 - 7/10c - 8 = 6 - 1/5c - 8

- 7/10c  = -2 - 1/5c

add 1/5c to both sides:

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change to common denominator:

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multiply both sides by -2:

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c = 4

___________________________________

question 2. 75 - 3.5y - 4y = 4y + 6 for y

75 - 3.5y - 4y = 4y + 6

75 - 7.5y = 4y + 6

add 7.5y to both sides:

75 - 7.5y + 7.5y = 4y + 6 + 7.5y

75 = 11.5y + 6

subtract 6 from both sides:

75 - 6 = 11.5y + 6 - 6

69 = 11.5y

divide both sides by 11.5:

69/11.5 = 11.5y/11.5

y = 6

___________________________________

Question 3. Solve the equation 16.5 + 2.75h = 9h + 7.5 − 4.25h for h.

16.5 + 2.75h = 9h + 7.5 − 4.25h

16.5 + 2.75h = 4.75h + 7.5

subtract 7.5 from both sides:

16.5 + 2.75h - 7.5 = 4.75h + 7.5 - 7.5

9 + 2.75h =  4.75h

subtract 2.75h from both sides:

9 + 2.75h - 2.75h =  4.75h - 2.75h

9 = 2h

divide both sides by 2:

9/2 = 2h/2

h = 9/2

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