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Mrrafil [7]
3 years ago
11

13. Find the equations of the straight lines which passes

Mathematics
1 answer:
ipn [44]3 years ago
3 0

9514 1404 393

Answer:

  • y = 1/2x +2
  • y = -2x +7

Step-by-step explanation:

The slope of a line is the tangent of the angle it makes with the x-axis. The given line has a slope of -1/3, so the lines we want will have slopes of ...

  m1 = tan(arctan(-1/3) +45°) = 0.5 . . . . . using a calculator

  m2 = tan(arctan(-1/3) -45°) = -2

Of course, these two lines are perpendicular to each other, so their slopes will have a product of -1: (0.5)(-2) = -1.

__

We can use the point-slope form of the equation for a line to write the desired equations:

  y = m(x -h) +k . . . . . line with slope m through point (h, k)

<u>Line 1</u>:

  y = 1/2(x -2) +3

  y = 1/2x +2

<u>Line 2</u>:

  y = -2(x -2) +3

  y = -2x +7

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Step-by-step explanation:

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2 years ago
Solve the equations if possible <br><br> * -5×=×+6(1-×)<br><br> *(2×-5)²=(2×-1)(2×+1)-10(2×-1)
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-5x = x + 6(1) + 6(-x)
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(2x-5)² = (2x-1)(2x+1) -10(2x-1)
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3 years ago
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