All categories

3 years ago

Evaluate functions g(0)=-x-2

Mathematics

1 answer:

Dvinal [7]3 years ago

6 0

Answer:

g(0) = -2

Step-by-step explanation:

g(x) = -x - 2

To find g(0), replace x with 0 in the equation.

g(0) = -0 - 2 = -2

You might be interested in

Help need ASAP please!

Tju [1.3M]

Answer:

I ANSWERED FIRST QUESTION

4A= 31.25X

4B=16

CUZ 500/31.25=16

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

PEACE!

8 0

4 years ago

Read 2 more answers

Adjacent=6 opposite=8 what is the hypotenuse

Umnica [9.8K]

Answer:

Step-by-step explanation:

pythagorean theory.

6^2+8^2=hypotenuse

36+64=√100

√100=10

4 0

3 years ago

Consider the following ordered data: 2 5 5 6 7 7 8 9 10 find Q3+1.5

Ksenya-84 [330]

You figure that your own >:(

6 0

3 years ago

Check down the image that’s give below

gregori [183]

Solution:

$\frac{3x}{ {x}^{2} + 6x + 9} + \frac{x + 3}{ {x}^{2} - 9 }$

In the first fraction, we have to factorise the denominator using (a + b)² = a² + 2ab + b². And in the second fraction, we have to factorise the denominator using a² - b² = (a - b)(a + b) identity.

$= \frac{3x}{ {(x)}^{2} + 2(x)(3) + ( {3)}^{2} } + \frac{x + 3}{(x)^{2} - (3)^{2} } \\ = \frac{3x}{(x + 3) ^{2} } + \frac{x + 3}{(x + 3)(x - 3)}$

From the second fraction, cancel out from both sides (x + 3), the we get:

$= \frac{3x}{(x + 3) ^{2} } + \frac{1}{(x - 3)} \\ = \frac{3x(x - 3) + 1(x + 3) ^{2} }{(x + 3)^{2} (x - 3)} \\ = \frac{3x ^{2} - 9 x+ {x}^{2} + 6x + 9}{ {(x + 3)}^{2} (x - 3)} \\ = \frac{ {4x}^{2} - 3x + 9}{(x + 3)(x + 3)(x - 3)}$

Answer:

$\frac{ {4x}^{2} - 3x + 9}{(x + 3)(x + 3)(x - 3)}$

Hope you could understand.

If you have any query, feel free to ask.

4 0

2 years ago

If this shape is 2 inches wide at every width of its 4 inch tall height, what is the area of this shape?

gogolik [260]

I think the answer is B) 8 in2.

5 0

4 years ago

Read 2 more answers