Answer:
8 seconds
Step-by-step explanation:
Given
h = - 5t² + 40t
When the object hits the ground then h = 0
Substitute h = 0 into the function and solve for t
- 5t² + 40t = 0 ← factor out - 5t from each term
- 5t(t - 8) = 0
Equate each factor to zero and solve for t
- 5t = 0 ⇒ t = 0
t - 8 = 0 ⇒ t = 8
t= 0 denotes the time of launch
t = 8 denotes the time it hits the ground
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Answer:
The equations shows a difference of squares are:
<u>10y²- 4x²</u> $ <u>6y²- x²</u>
Step-by-step explanation:
the difference of two squares is a squared number subtracted from another squared number, it has the general from Ax² - By²
We will check the options to find which shows a difference of squares.
1) 10y²- 4x²
The expression is similar to the general form, so the equation represents a difference of squares.
It can be factored as (√10 y + 2x )( √10 y - 2x)
2) 6y²- x²
The expression is similar to the general form, so the equation represents a difference of squares.
It can be factored as (√6y + x )( √6y - x)
3) 8x²−40x+25
The expression is not similar to the general form, so the equation does not represent a difference of squares.
4) 64x²-48x+9
The expression is not similar to the general form, so the equation does not represent a difference of squares.
Answer:
456
Step-by-step explanation:
