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8_murik_8 [283]
3 years ago
14

Please help ! select all that apply.

Mathematics
2 answers:
nadezda [96]3 years ago
7 0

Answer:

All expect the first one

Step-by-step explanation:

Ipatiy [6.2K]3 years ago
6 0

Answer:

A and B

Step-by-step explanation:

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My bed is 3 inches by 2and 2/3 inches by 1/3<br> inch. What is the volume of my bed?
ki77a [65]

Step-by-step explanation:

volume \: of \: bed  \\  \\ = 3 \times 2 \frac{2}{3}  \times  \frac{1}{3}   \\ \\  = 3 \times  \frac{8}{3}  \times  \frac{1}{3}  \\  \\  =  \frac{8}{3}  \\  \\  = 2 \frac{2}{3}  \:  {inch}^{3}

7 0
3 years ago
Read 2 more answers
Which equation shows y=−1/2x+4 is in standard form?
adelina 88 [10]

Answer:

B. x + 2y = 8 is your answer.

Step-by-step explanation:

So this is what you do:

y = -1/2x + 4 <u>You are going to add -1/2 to the other side.</u>

y + 1/2x = 4 <u>You are going to multiply the equation by 2.\</u>

B. x + 2y = 8 is your answer.

8 0
4 years ago
What does the fact that the expressions are equivalent mean?
NNADVOKAT [17]

Answer:

The fact that the expressions are equivalent means that for any value of the variables, the two expressions have the same solution.

Step-by-step explanation:

3 0
3 years ago
Write an expression for this one <br> the sum of an odd integer and the next odd integer.
Sidana [21]
Let x is the odd integer
x +2 is the next odd integer
so sum of an odd integer and the next odd integer:
x + (x+2) 
8 0
3 years ago
Show how to find the roots (zeros) of the function in the picture below.
Vikki [24]

Answer:

The roots (zeros) of the function are:

x=5,\:x=-8

Step-by-step explanation:

Given the function

f\left(x\right)=x^2+3x-40

substitute f(x) = 0 to determine the zeros of the function

0=x^2+3x-40

First break the expression x² + 3x - 40  into groups

x² + 3x - 40 = (x² - 5x) + (8x - 40)

Factor out x from x² - 5x:  x(x - 5)

Factor out 8 from 8x - 40:  8(x - 5)

Thus, the expression becomes

0=x\left(x-5\right)+8\left(x-5\right)

switch the sides

x\left(x-5\right)+8\left(x-5\right)=0

Factor out common term x - 5

(x - 5) (x + 8) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x-5=0\quad \mathrm{or}\quad \:x+8=0

Solve x - 5 = 0

x - 5 = 0

adding 5 to both sides

x - 5 + 5 = 0 + 5

x = 5

solve x + 8 = 0

x + 8 = 0

subtracting 8 from both sides

x + 8 - 8 = 0 - 8

x = -8

Therefore, the roots (zeros) of the function are:

x=5,\:x=-8

6 0
3 years ago
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