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Fantom [35]
3 years ago
7

Help me please!!!!!!!!!!!!

Mathematics
1 answer:
iVinArrow [24]3 years ago
6 0

Answer: 0.25g<2.50.... g<10

Step-by-step explanation: Let us say that the number of gumballs bought is represented by the variable g. In this case, the question is asking how many gumballs can be bought without surpassing the price of $2.50. We know that each gumball is $0.25, therefore the number of gumballs we buy times $0.25 has to be less than $2.50. Hence, the inequality would be 0.25g<2.50. If we were to solve this then g<2.50/0.25-----> g<10. In conclusion, the number of gumballs you can buy has to be less than 10. Thank you!

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Use the distance formula to find the perimeter of the triangle below. Round you answer to the nearest hundredth. ​
Murrr4er [49]

<u>jAlright, let's take this problem step-by-step</u>:

<u>What is the perimeter</u>:

 ⇒ all the side-lengths added up

    ⇒ <em>need</em> to find side-length using distance formula

                Distance_._. Formula=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

                         - (x₁,y₁): first point

                         - (x₂,y₂): second point

<u>Let's solve</u>:

  • Find length of <em>AC</em>

           ⇒ <em>first point</em>: (5,7)

<em>            ⇒ second point: </em>(3,3)

<em>            </em>Distance =\sqrt{(3-5)^2+(3-7)^2} =\sqrt{4+16} =\sqrt{20} =4.472

  • Find length of AB

          ⇒ <em>first point:</em> (5,7)

<em>           ⇒ second point:</em>(8,6)

<em>            </em>Distance=\sqrt{(8-5)^2+(6-7)^2} =\sqrt{9+1} =\sqrt{10}=3.162

  • Find length of BC

          ⇒<em> first point: </em>(8,6)

<em>           ⇒ second point: </em>(3,3)

<em>            </em>Distance = \sqrt{(3-8)^2+(3-6)^2} =\sqrt{25+9} =\sqrt{34}=5.831

<u>Now let's solve for the perimeter</u>:

  Perimeter = 4.472+ 3.126+ 5.831=13.429

<u>Answer: 13.43</u> (<em>rounded to the nearest hundredth)</em>

Hope that helps!

#LearnwithBrainly

<em>               </em>

5 0
2 years ago
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