Answer: If a system has infinitely many solutions, then the lines overlap at every point. In other words, they're the same exact line so this means that any point on the line is a solution to the system.
Step-by-step explanation: Hope this helps
Answer:
OR {5, 6, 7, 8, .....}
Step-by-step explanation:
First of all, let us have a look at the interval shown on the number line and try to understand it properly.
The number line shows positive numbers starting from 3 that means numbers indicated will be positive numbers.
The number highlighted starts from 5 and there is filled circle at 5.
So, 5 is included in the interval.
The arrow is from 5 towards 8 and so on..
That means Numbers greater than or equal to 5 are represented by the interval.
So, writing as an inequality
Let 
represents one of the numbers.
Hence, inequality can be written as:
Using the set notation:
OR
{5, 6, 7, 8, .....}
Answer:
4a. S = 300c
4b. S = 2400
Step-by-step explanation:
4a. There are 300 seats in a conference room 'c' so to find the amount of seats there are in total you need to times these values so...
S = 300c
4b. substituting 8 into c gets
S = 300x8
S = 2400
hope this helps!
Answer:
Thirty Residents Who Live Within a 2-Miles Radius Of Natasha’s School
Step-by-step explanation:
1119/2
Equations may be true or false, just as word sentences may be true or false. The equation:
3 + x = 7
will be false if any number except 4 is substituted for the variable. The value of the variable for which the equation is true (4 in this example) is called the solution of the equation. We can determine whether or not a given number is a solution of a given equation by substituting the number in place of the variable and determining the truth or falsity of the result.
Example 1 Determine if the value 3 is a solution of the equation
4x - 2 = 3x + 1
Solution We substitute the value 3 for x in the equation and see if the left-hand member equals the right-hand member.
4(3) - 2 = 3(3) + 1
12 - 2 = 9 + 1
10 = 10
Ans. 3 is a solution.
The first-degree equations that we consider in this chapter have at most one solution. The solutions to many such equations can be determined by inspection.
Example 2 Find the solution of each equation by inspection.
a. x + 5 = 12
b. 4 · x = -20
Solutions a. 7 is the solution since 7 + 5 = 12.
b. -5 is the solution since 4(-5) = -20.
