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Sedaia [141]
4 years ago
7

Solve - 2 x 3 + 22 - 8 - 2 = in a exponent 3 + 3 + 3 + 3 + 3

Mathematics
2 answers:
kow [346]4 years ago
7 0
2 x 3 = 6 

6 + 22 = 28

28 - 8 = 20

20 - 2 = 18


3 + 3 + 3 + 3 + 3 as a exponent is 3^{5}

Because it says 3 5 times!

Hope this helped!
zalisa [80]4 years ago
3 0
- 2(3) + 22 - 8 - 2= 
-6 + 12 = 
6

3 + 3 + 3 + 3 + 3 = 15

3 x 3 x 3 x 3 x 3 = 3^5  (because there are 5 threes multiplied together)

-2x^3 + 22 - 8 - 2 = 
-2x^3 + 12 

hope this helps
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Aliun [14]

Answer:

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Step-by-step explanation:

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2 years ago
Using a calculator.. I need help please .
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Answer:

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6 0
3 years ago
A certain bowler can bowl a strike 85 % of the time. What is the probability that she ​a) goes three consecutive frames without
Artist 52 [7]

Answer:

a) 0.34% probability that she goes three consecutive frames without a​ strike.

b) 1.91% probability that she her first strike in the third ​frame

c) 99.66% probability that she has at least one strike in the first three ​frames.

d) 14.22% probability that she bowls a perfect game.

Step-by-step explanation:

For each frame, there are only two possible outcomes. Either there is a strike, or there is not. The probability of a strike happening in a frame is independent of other frames. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A certain bowler can bowl a strike 85 % of the time.

This means that p = 0.85

a) goes three consecutive frames without a​ strike?

This is P(X = 0) when n = 3. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.85)^{0}.(0.15)^{3} = 0.0034

0.34% probability that she goes three consecutive frames without a​ strike.

​b) makes her first strike in the third ​frame?

No strike during the first two(with a 15% probability)

Strike during the third(85% probability). So

P = 0.15*0.15*0.85 = 0.0191

1.91% probability that she her first strike in the third ​frame

c) has at least one strike in the first three ​frames? ​

Either there are no strikes, or there is at least one strike. The sum of the probabilities of these events is 100%.

From a), 0.34% probability that she goes three consecutive frames without a​ strike.

100 - 0.34 = 99.66

99.66% probability that she has at least one strike in the first three ​frames.

d) bowls a perfect game​ (12 consecutive​ strikes)?

This is P(X = 12) when n = 12. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 12) = C_{12,12}.(0.85)^{12}.(0.15)^{0} = 0.1422

14.22% probability that she bowls a perfect game.

3 0
4 years ago
If f(x)=.5x+15 , what is the value of f(-4)​
Levart [38]
  • <em>Answer:</em>

<em>f(-4) = 13</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>f(x) = 0.5x + 15</em>

<em>replace x = - 4</em>

<em>f(-4) = 0.5×(-4) + 15</em>

<em>= - 2 + 15</em>

<em>= 15 - 2</em>

<em>= 13</em>

<em>Good luck !</em>

8 0
3 years ago
5. Following data indicates the number of vehicles arrived during past
pantera1 [17]

Answer:

what are you supposed to do here?

Step-by-step explanation:

8 0
4 years ago
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