Ask question

Ask question

All categories

3 years ago

11

David uses 1/4 bag of potting soil to plant 6 tomato plants. If he uses the same amount of potting soil for each plant, what fra

ction of the bag of potting soil will each plant get?
1/24
24
2/3
1 1/2

1 answer:

Schach [20]3 years ago

8 0

Answer:

Step-by-step explanation:

A

You might be interested in

Multiplying two complex numbers involves ______.

Alenkasestr [34]

Answer:

Multiplying a complex number by a real number

(x + yi) u = xu + yu i. In other words, you just multiply both parts of the complex number by the real number. For example, 2 times 3 + i is just 6 + 2i. Geometrically, when you double a complex number, just double the distance from the origin, 0.

binomial methods

Complex numbers use binomial methods of multiplication because unlike real numbers, imaginary numbers have two components.

So probably A. I sorry, but I need more information. Hope this helps

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Why is it important to consider scale when graphing inequalities?

Natali5045456 [20]

Answer:

Because to get a straight line you need a scale. Otherwise you will not be able to graph a straight line.

Hope this helps:)

5 0

2 years ago

HELP ASAP PLEASE

Verizon [17]

Answer:

1.25 g

Step-by-step explanation:

<u>Given:</u>

Initial mass is m = 80 g.
Half life = 10 days
Total time = 60 days

<u>Number of half-life periods:</u>

r = 60/10 = 6

<u>Equation for remaining sample:</u>

s = m*(1/2)^r
s = 80*(1/2)^6 = 80/64 = 1.25 g

5 0

2 years ago

Help me asap! I will give you marks

Law Incorporation [45]

Recall the binomial theorem.

$(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k$

1. The binomial expansion of $\left(1+\frac x3\right)^7$ is

$\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}$

Observe that

$k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x$

$k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2$

When we multiply these by $8-9x$ ,

• $8$ and $\frac73 x^2$ combine to make $\frac{56}3 x^2$

• $-9x$ and $\frac73 x$ combine to make $-\frac{63}3 x^2 = -21x^2$

and the sum of these terms is

$\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}$

2. The binomial expansion is

$\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k$

We get the $a^6b^2$ term when $k=2$ :

$k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2$

6 0

1 year ago

UNO [17]

Answer:

PUSHIN

Step-by-step explanation:

6 0

2 years ago