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3 years ago

8

May I please receive help?

1 answer:

Neporo4naja [7]3 years ago

6 0

Answer:

good luck mate

Step-by-step explanation:

good luck

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How do I solve this?

Ivenika [448]

$\overline{XS}\cong\overline{YT}\Rightarrow 3m+7=4.2m+5\ \ \ |-7\\\\3m=4.2m-2\ \ \ \ |-4.2m\\\\-1.2m=-2\ \ \ \ |:(-1.2)\\\\m=\dfrac{2}{1.2}\\\\m=\dfrac{20}{12}\\\\m=\dfrac{5}{3}\to m=1\dfrac{2}{3}$

$\overline{YS}\cong\overline{XT}\Rightarrow3\dfrac{1}{2}r+2=2r+5\ \ \ \ |-2\\\\3\dfrac{1}{2}r=2r+3\ \ \ \ |-2r\\\\1\dfrac{1}{2}r=3\ \ \ |\cdot2\\\\3r=6\ \ \ \ |:3\\\\r=2$

7 0

3 years ago

Y=f(x)=(1/6)^x find f(x) when x=1/4

SashulF [63]

I think it is 0.64..

5 0

4 years ago

Read 2 more answers

user100 [1]

If you are talking about what is in between the two sets of parentheses then the answer would be multiplication hope that helped

8 0

3 years ago

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ਕind me<br>When x = 4 and y = 3, find the value of:<br>a) 2x + 7y - 10

Andre45 [30]

Answer:

19

Step-by-step explanation:

by replacing x and y with their given values ,

we get :-

=》2x + 7y - 10

=》(2 × 4) + (7 × 3) - 10

=》8 + 21 - 10

=》29 - 10

=》19

5 0

3 years ago

What are the solutions to the quadratic equation below in factored form?

saw5 [17]

Answer:

$\cfrac{-4}{3}$ and $\cfrac{1}{2}$ .

Step-by-step explanation:

Equation:

$\rm \: \: (2x - 1)(3x + 4) = 0$

Solution:

Set factors equal to zero,that is:

$(2x - 1) = 0 \: \: \: \: \: \: \: \: \: \: \: ...(1)$

$(3x + 4) = 0 \: \: \: \: \: \: \: \: \: \: \: \: ...(2)$

Solving for equation 1:

$2x - 1 = 0$
$2x = 0 + 1$
$2x = 1$

$\boxed{x = \cfrac{ 1}{2} }$

Solving for equation 2:

$3x + 4 = 0$
$3x = 0 - 4$
$3x = - 4$

$\boxed{x = \cfrac{ - 4}{3} }$

Hence,the solutions to the quadratic equation in factored form is $\cfrac{-4}{3}$ and $\cfrac{1}{2}$ .

$\rule{225pt}{2pt}$

Good luck on your assignment!

4 0

2 years ago

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