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n200080 [17]
3 years ago
3

A magazine article reported that college students spend an average of $100 on a first date. A university sociologist believed th

at number was too high for the students at the university. The sociologist surveyed 32 randomly selected students from the university and obtained a sample mean of $92.23 for the most recent first dates. A one-sample t-test resulted in a P-value of 0.026. Which of the following is a correct interpretation of the P-value?
a) The probability is 0.026 that the mean amount of money students from the university spend on a first date is less than $100.
b) The probability is 0.026 that the mean amount of money students from the university spend on a first date is less than $92.23.
c) The probability is 0.026 that the mean amount of money students from the university spend on a first date is more than $92.23.
d) If the mean amount of money that students from the university spend on a first date is $100, the probability is 0.026 that a randomly selected group of 32 students from the university would spend a mean of $92.23 or less on their most recent first dates.
e) If the mean amount of money that students from the university spend on a first date is less than $100, the probability is 0.026 that a randomly selected group of 32 students from the university would spend a mean of $92.23 or less on their most recent first dates.
Mathematics
1 answer:
Flauer [41]3 years ago
3 0

Answer:

The correct option is (d).

Step-by-step explanation:

The <em>p</em>-value is well defined as the probability, [under the null hypothesis (<em>H₀</em>)], of attaining a result equivalent to or more extreme than what was the truly observed value of the test statistic.

We reject a hypothesis if the <em>p</em>-value of a statistic is lower than the level of significance <em>α</em>.

A small <em>p</em>-value (typically ≤ 0.05) specifies solid proof against the null hypothesis (<em>H₀</em>), so you discard <em>H₀</em>.

A large <em>p</em>-value (> 0.05) specifies fragile proof against the <em>H₀</em>, so you fail to discard <em>H₀</em>.

The hypothesis in this case can be defined as follows:

<em>H₀</em>: The mean amount of money students from the university spend on a first date is $100, i.e. <em>μ</em> = 100.

<em>Hₐ</em>: The mean amount of money students from the university spend on a first date is less than $100, i.e. <em>μ</em> < 100.

The sample selected is of size, <em>n</em> = 32.

The sample mean amount spent is, $92.23.

The <em>p</em>-value of the test is, <em>p</em>-value = 0.026.

The <em>p</em>-value in this case can be defined as the probability that the sample mean amount spent on first date by the 32 students is less than or equal to $92.23, given that the actual mean amount spent on first date is $100.

Thus, the correct option is (d).

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Two friends sold many pieces of furniture and made ​$1550 during their garage sale. They had fifteen more​ $10 bills than​ $50 b
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The number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

Step-by-step explanation:

Let n₁ = number of $ 10 bills,

Let n₂ = number of $ 20 bills and

Let n₃ = number of $ 50 bills

Given that 10n₁ + 20n₂ + 50n₃ = 1550    (1)

Also, since we have fifteen more​ $10 bills than​ $50 bills, n₁ = n₃ + 15  (2)

and we have 4 more than three times as many​ $20 bills as​ $50 bills. n₃ = 3n₂ + 4. (3)

substituting equations (2) and (3) into (1), we have

10(n₃ + 15) + 20n₂ + 50n₃ = 1550

expanding the bracket, we have

10n₃ + 150 + 20n₂ + 50n₃ = 1550

collecting like terms, we have

60n₃ + 150 + 20n₂ = 1550

inserting equation (3), we have

60(3n₂ + 4) + 150 + 20n₂ = 1550

expanding the bracket, we have

180n₂ + 240 + 150 + 20n₂ = 1550

collecting like terms, we have

200n₂ + 390 = 1550

subtracting 390 from both sides, we have

200n₂ = 1550 - 390

200n₂ = 1160

dividing both sides by 200, we have

n₂ = 1160/200

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n₂ ≅ 6 since it cannot be a fraction.

Substituting this into (3), we have

n₃ = 3n₂ + 4 = 3(6) + 4 = 18 + 4 = 22

substituting n₃ into (2), we have

n₁ = n₃ + 15 = 22 + 15 = 37

So, the number of $ 10 bills is 37, the number of $ 20 is 6 and the number of $ 50 bills is 22.

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