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White raven [17]
3 years ago
8

Cindy paid $2.58 for a 2/3 pounds of sunflower seeds. how much does each pound of sunflower cost?

Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

3.87

Step-by-step explanation:

2.58/2=1.29=1/3 pounds

1.29*3=3.87

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Scores on the SAT Mathematics test are believed to be normally distributed. The scores of a simple random sample of five student
AysviL [449]

Answer:

The mean calculated for this case is \bar X=584

And the 95% confidence interval is given by:

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=584

The sample deviation calculated s=86.776

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.776

Now we have everything in order to replace into formula (1):

584-2.776\frac{86.776}{\sqrt{5}}=476.271    

584+2.776\frac{86.776}{\sqrt{5}}=691.729    

So on this case the 95% confidence interval would be given by (476.271;691.729)    

3 0
3 years ago
The Fun Committee is hosting the Annual City Festival. Jennifer is in charge of the committee and is planning a race to raise mo
nadya68 [22]

Answer: Hello your question some data but i will provide a general solution based on the scope of your question making some suggestions as well

answer : Summation of displacements ( back and forth distance ) / Number of Runners

Step-by-step explanation:

Given that ; the aim of the race is to raise money

The number of miles/ distance covered will determine how much money that would be raised

Formula to resolve the problem =  Summation of displacements ( back and forth distance ) / Number of Runners

<em>Lets assume: ( example ) </em>

<em> Distance between the Park and the City hall is = 6 miles </em>

<em>Number of runners = 4</em>

<em>Given that the runners Run  from the Park to the City hall and then run back</em>

<em>Total miles covered by each runner = ( 6 + 6 )/ 4  = 12/4 = 3 miles </em>

4 0
3 years ago
Please help !!!!!!!!!!!!!​
arlik [135]

Answer:

Step-by-step explanation:

7 0
3 years ago
Is 12.14 bigger than 12.44
RideAnS [48]
No 12.14 is not bigger than 12.44

12.14 < 12.44
5 0
3 years ago
Read 2 more answers
Michaels buys three over a pound of cheese he puts the same amount of cheese and three sandwiches how many cheese how much chees
Tasya [4]

Question is not proper,Proper question is given below;

Nicholas buys 3/8 pound of cheese he put the same amount of cheese and three sandwiches how much cheese does Nicholas put on each sandwich

Answer:

Nichole can put \frac{1}{8} \ pounds of cheese on each of his sandwich.

Step-by-step explanation:

Total Amount of cheese he has = \frac{3}{8} \ pound

Number of cheese sandwiches = 3

We need to find Amount of cheese does Nicole put on each of his sandwich.

Solution:

Amount of cheese on each sandwich can be calculated by dividing Total Amount of cheese he has with Number of cheese sandwiches.

framing in equation form we get;

Amount of cheese on each sandwich = \frac{\frac{3}{8}}{3}} = \frac{1}{8} \ pounds

Hence Nichole can put \frac{1}{8} \ pounds of cheese on each of his sandwich.

7 0
3 years ago
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