Answer:
A positive times a negative will always be a negative and when u divide a positive by a negative the same rules apply so it will be a negative
If we take the square of x and square of y and then subtract them:
(csc t)²-(cot t)²=1 ( this eq. gets from basic identity
x²-y²=1......a 1+cot²x=csc²x)
equation 'a' represent the equation of hyperbola which is (x²/a²)-(y²/b²) =1 with given conditions( a=1,b=1)
So, option D is correct
Answer:
(-3, 4)
Step-by-step explanation:
First, add 3 to point B's x coordinate:
-6 + 3 = -3
Then, add 1 to the y coordinate:
3 + 1
= 4
So, the coordinates of pre image point A are (-3, 4)
Mark me as brainliest please! :)
The point-slope form of equation is
y
+
4
=
6
⋅
(
x
−
3
)
Explanation:
Point - Slope form of a linear equation is
(
y
−
y
1
)
=
m
⋅
(
x
−
x
1
)
Given : Slope
m
=
6
, Point
(
x
1
,
y
1
)
=
(
3
,
−
4
)
The point-slope form of equation is
y
+
4
=
6
⋅
(
x
−
3
)
A = 11 and b = 8 I’m pretty sure brosky
