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Nesterboy [21]
3 years ago
11

What are the vertices of AA'B'C'if AABC is dilated by a scale factor of 4?

Mathematics
1 answer:
ss7ja [257]3 years ago
6 0

Answer:

B

Step-by-step explanation:

Assuming the dilatation is centred at the origin, then multiply each of the coordinates by 4 , that is

A (0, 10 ) → A' (4(0), 4(10) ) → A' (0, 40 )

B (8, 6 ) → B' (4(8), 4(6) ) → B' (32, 24 )

C (4, 2 ) → C' (4(4), 4(2) ) → C' (16, 8 )

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Step-by-step explanation

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2 years ago
X/5 = 2 1/2<br><br> Fraction <br> Have to find x
nadya68 [22]

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3 years ago
Factor 4x 2 + 12x + 5 . (2x + 5)(2x + 1)
Juliette [100K]
Factor
in form
ax²+bx+c form
use the ac method
1. mulitply a and c
2. factor the result such that the 2 factors add to b
3. split b into those 2 factors
4. group the terms
5. undistribute common factors
6. undistribute again





first multiply ac
4 times 5=20
now
what 2 numbers multiply to 20 and add to 12
2 and 10
4x²+2x+10x+5
group
(4x²+2x)+(10x+5)
undistribute
2x(2x+1)+5(2x+1)
undistribute the (2x+1)
(2x+1)(2x+5) is factored form whih you have there, nice
8 0
3 years ago
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