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kozerog [31]
3 years ago
12

Create your own quadratic function in standard form with a Y intercept is 9

Mathematics
1 answer:
S_A_V [24]3 years ago
3 0

Answer:

\boxed{\sf \ \ x^2+9 \ \ }

Step-by-step explanation:

Hello,

y=f(x)=x^2+9

as for x = 0 y = 9

Hope this helps

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Jane is standing at the base of a 6300ft tall mountain. If she climbs 15% of the remaining height each day, how many feet will s
Andrews [41]

Answer:

Total ft climbed= 3,011.36

Step-by-step explanation:

<u>Giving the following information:</u>

Total ft= 6,300

Climbing rate= 15% of the remaining height per day

<u>Total ft climbed per day:</u>

Day 1= 6,300*0.15= 945

Day 2= (6,300 - 945)*0.15= 803.25

Day 3= (5,355 - 803.25)*0.15= 682.76

Day 4= (4,551.75 - 682.76)*0.15= 580.35

Total ft climbed= 3,011.36

4 0
3 years ago
Austin is going for a walk. He takes 3 hours to walk 4.8 miles. What is his speed?
Alexxandr [17]
I hope this helps you



3 0
3 years ago
Rectangle PQRS is rotated 90 counterclockwise about the origin what are the coordinates of point Q
inna [77]
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.

When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)

Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)

point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)

point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)

Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)

Hope this helps :)
5 0
3 years ago
Read 2 more answers
I need help with #8. I need to use the quadratic formula. I have a calculator that is programmed for the quadratic formula so al
GuDViN [60]

Answer:

  x = 14

Step-by-step explanation:

Extend line AB so that it intersects ray CE at point G. Then angles BGC and BAD are "alternate interior angles", hence congruent.

The angle at B is exterior to triangle BCG, and is equal to the sum of the interior angles at C and G:

  138 = (376 -23x) +(x^2 -8x)

Subtracting 138 and collecting terms we have ...

  x^2 -31x +238 = 0

For your calculator, a=1, b=-31, c=238.

__

<em>Additional comment</em>

You will find that the solutions to this are x = {14, 17}. You will also find that angle BCE will have corresponding values of 54° and -15°. That is, the solution x=17 is "extraneous." It is a solution to the equation, but not to the problem.

For x=14, the marked angles are A = 84°, C = 54°.

8 0
3 years ago
For each value of y , determine whether it is a solution to -21=6y-9 . A -5, B 3 , C -2, D 9
Nezavi [6.7K]

Option C

For each value of y, -2 is a solution of -21 = 6y - 9

<u>Solution:</u>

Given, equation is – 21 = 6y – 9  

We have to find that whether given set of options can satisfy the above equation or not

Now, let us check one by one option

<em><u>Option A) </u></em>

Given option is -5

Let us substitute -5 in given equation

- 21 = 6(-5) – 9

- 21 = -30 – 9  

- 21 = - 39  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option B)</u></em>

Given option is 3

- 21 = 6(3) – 9  

- 21 = 18 – 9  

- 21 = 9  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option C)</u></em>

Given option is -2

- 21 = 6(-2) – 9  

- 21 = - 12 – 9  

- 21 = - 21  

L.H.S = R.H.S ⇒ yes a solution

<em><u>Option D)</u></em>

- 21 = 6(9) – 9

- 21 = 54 – 9  

- 21 = 45  

L.H.S ≠ R.H.S ⇒ not a solution

Hence, the solution for the given equation is – 2, so option c is correct

6 0
3 years ago
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