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2 years ago

Select all the following that could

Mathematics

1 answer:

liraira [26]2 years ago

5 0

Answer:

A ; C ; D

Step-by-step explanation:

Volume of a rectangular prism:

V = l x w x h

1) 5 x 4 x 3 = 60 (ok)

2) 25 x 20 x 15. The result is > 60

3) 5 x 2 x 6 = 60 (ok)

4) 4 x 1 x 15 = 60 (ok)

5) 5 x 8 x 2 = 80

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For a normally distributed random variable x with m = 75 and s = 4, find the probability that 69 < x < 79 Use the table to

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2 years ago

There are 24 muffins in a bakery. If 3/8 of the muffins are blueberry, how many muffins are strawberrie?

Lorico [155]

3/8 = 9 blueberry muffins so 15 (or 5/8) of the muffins should be strawberry if that's the only other kind of muffins in this equation.

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2 years ago

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kobusy [5.1K]

Answer:

B. 15"

Step-by-step explanation:

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2 years ago

Reuben has scores of 70,75,83, and 80 on four spanish quizzes. what score must he get on the next quiz to achieve an average of

Sergio [31]

X - the score he must get

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He must get at least 92 points.

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2 years ago

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1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the

Musya8 [376]

Answer:

A) 34.13%

B) 15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

$z=\frac{x-m}{s}$

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

$z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0$

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

= 0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

$P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587$

C) Between 80 and 120

$P( 80$

D) less than 80

$P( x < 80 ) = P( z$

E) Between 70 and 100

$P( 70$

F) More than 130

$P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013$

8 0

2 years ago