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lina2011 [118]
3 years ago
13

Select the letter of the best answer choice. Use 3.14 or 22/7 for π

Mathematics
1 answer:
valkas [14]3 years ago
5 0
C = 2πr
141.3 = 2(3.14)r
141.3 = 6.28r
22.5 = r
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A business has $10,000 in its bank account. In order to build an addition onto its office, it takes out a loan for $30,000 and d
ser-zykov [4K]

Answer:

The new account balance is $40000

Step-by-step explanation:

<em>The number line is not given. However, the question can be solved without it.</em>

Given

Balance = \$10000

Loan = \$30000

Required

Determine the new balance

New\ Balance = Initial\ Balance + Loan\ Amount

New\ Balance = \$10000 + \$30000

New\ Balance = \$40000

Hence:

<em>The new account balance is $40000</em>

7 0
3 years ago
Solve the proportion t+4 / t-2 = 1/4
Lera25 [3.4K]

t+4 / t-2 = 1/4

t=-6 for your answer!

8 0
3 years ago
Use a calculator to find a decimal approximation for the following trigonometric function sin 28°48
Bumek [7]

The decimal approximation for the trigonometric function sin 28°48' is

Given the trigonometric function is sin 28°48'

The ratio between the adjacent side and the hypotenuse is called cos(θ), whereas the ratio between the opposite side and the hypotenuse is called sin(θ). The sin(θ) and cos(θ) values for a given triangle are constant regardless of the triangle's size.

To solve this, we are going to convert 28°48' into degrees first, using the conversion factor 1' = 1/60°

sin (28°48') = sin(28° ₊ (48 × 1/60)°)

= sin(28° ₊ (48 /60)°)

= sin(28° ₊ 4°/5)

= sin(28° ₊ 0.8°)

= sin(28.8°)

= 0.481753

Therefore sin (28°48') is 0.481753.

Learn more about Trigonometric functions here:

brainly.com/question/25618616

#SPJ9

5 0
2 years ago
Plzzz answer question number 2 I will give you 100 points
nirvana33 [79]
Arabia because she has the largest numbers
3 0
3 years ago
Read 2 more answers
AABC has vertices at A(1, -9), B(8,0), and C(9,-8).
Rainbow [258]

Check the picture below.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill

B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

6 0
2 years ago
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