Options: y = 8/5x - 1/2 y = - 5/8x - 1/2 y = 8/5x + 1/2 y = 5/8x

What is the slope of the line that contains the point -6,-7 and -6,2

Masja [62]

We know that coordinates are labeled (x,y)
The formula to find slope is (Y2-Y1)/(X2-X1)
So (2- (-7))/(-6-(-6) undefined because the denominator is zero. The line looks like a vertical line at x=-6

8 0

3 years ago

Read 2 more answers

Solve the following equation for x. 12x - 8 = 40 A. 4 B. 5 C. 6 D. 3

Anon25 [30]

Add 8 to both sides

12x = 40 + 8

Simplify 40 + 8 to 48

12x = 48

Divide both sides by 12

x = 48/12

Simplify 48/12 to 4

x = 4

Answer: A. 4

7 0

3 years ago

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Lydia inherited a sum of money. She split it into five equal parts. She invested three parts of the money in a high-interest ban

babunello [35]

I beileive he inherited 1,176.45 i tried to put my work on here but i couldnt find a way that it would make sense

3 0

3 years ago

This is a 3 part 1 question each part on how to locate the plane and a small explanation report working out the recovery details

sesenic [268]

Third leg.

The crew flies at a speed of 560 mi/h in direction N-20°-E.

The wind has a speed of 35 mi/h and a direction S-10°-E.

We then can draw this as:

We have to add the two vectors to find the actual speed and direction.

We will start by adding the x-coordinate (W-E axis):

$\begin{gathered} x=560\cdot\sin (20\degree)+35\cdot\sin (10\degree) \\ x\approx560\cdot0.342+35\cdot0.174 \\ x\approx191.53+6.08 \\ x\approx197.61 \end{gathered}$

and the y-coordinate (S-N axis) is:

$\begin{gathered} y=560\cdot\cos (20\degree)-35\cdot\cos (10\degree) \\ y\approx560\cdot0.940-35\cdot0.985 \\ y\approx526.23-34.47 \\ y\approx491.76 \end{gathered}$

Then, the actual speed vector is v3=(197.61, 491.76).

The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].

Then, we have to calculate the displacement in 20 minutes using the actual speed vector.

We can calculate the movement in each of the axis. For the x-axis:

$\begin{gathered} R_{3x}=R_{2x}+v_{3x}\cdot t \\ R_{3x}=216.66+197.61\cdot\frac{1}{3} \\ R_{3x}=216.66+65.87 \\ R_{3x}=282.53 \end{gathered}$

NOTE: 20 minutes represents 1/3 of an hour.

We can do the same with the y-coordinate:

$\begin{gathered} R_{3y}=R_{2y}+v_{3y}\cdot t \\ R_{3y}=167.67+491.76\cdot\frac{1}{3} \\ R_{3y}=167.67+163.92 \\ R_{3y}=331.59 \end{gathered}$

The final position is R3 = (282.53, 331.59).

To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:

The distance can be calculated as if it was a right triangle:

$\begin{gathered} d^2=x^2+y^2_{} \\ d^2=282.53^2+331.59^2 \\ d^2=79823.20+109951.93 \\ d^2=189775.13 \\ d=\sqrt[]{189775.13} \\ d\approx435.63 \end{gathered}$

The angle, from E to N, can be calculated as:

$\begin{gathered} \tan (\alpha)=\frac{y}{x} \\ \tan (\alpha)=\frac{331.59}{282.53} \\ \tan (\alpha)\approx1.1736 \\ \alpha=\arctan (1.1736) \\ \alpha=49.56\degree \end{gathered}$

If we want to express it from N to E, we substract the angle from 90°:

$\beta=90\degree-\alpha=90-49.56=40.44\degree$

Answer: the final location can be represented with the vector (282.53, 331.59).

1) The distance from the origin is 435.63 miles and

2) the direction is N-40°-E.

7 0

1 year ago

Determine whether each sequence is arithmetic or geometric. Find the next three terms.

damaskus [11]

You don't know your terms I suppose.

Arithmetic: goes from one term to the next by adding or subtracting the same amount
Ex. 3,12,21,30,39 (d=9)
(d means difference, use this for arithmetic sequences)

Geometric: goes from one term to the next by multiplying or dividing by the same amount
Ex. 1,2,4,8,16,32,64,128 (r=2) (r means ratio, its just the number multiplied or divided each time)

Answer is c

4 0

3 years ago

Options: y = 8/5x - 1/2 y = - 5/8x - 1/2 y = 8/5x + 1/2 y = 5/8x - 1/2