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3 years ago

If 2x +4=b, then 6x + 12=

Mathematics

2 answers:

schepotkina [342]3 years ago

7 0

Answer:

Step-by-step explanation:

2x + 4 = b

3(2x+4) = 3b

6x + 12 = 3b

forsale [732]3 years ago

6 0

Answer:

Step-by-step explanation:

(2x+4)*3=b*3

6x+12=3b

That is what i learned from school, hopes this helps

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

How do you know that 8 over 10 and 48 over 60 are equivalent

beks73 [17]

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3 0

4 years ago

Read 2 more answers

Answer. it fast please

mojhsa [17]

Answer:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

Step-by-step explanation:

Given

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Required

Solve:

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Simplify 6/10

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2$

Express 9 as 3^2

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2$

Apply law of indices

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}$

Express as a sing;e fraction

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}$

Apply law of indices:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

5 0

3 years ago

- I need help on this one too same test different question-

Zanzabum

Answer:

Supplementary

Step-by-step explanation:

3 0

3 years ago