2 years ago

Find the slope of the line that passes through the points (9, -2) and (4, 3)

Mathematics

1 answer:

klemol [59]2 years ago

4 0

Answer:

-x aka -1

Step-by-step explanation:

x1 y1 x2 y2

9 -2 4 3

m= y2 - y1/x2 - x1

m = 3 + 2/4 - 9

(The "-" sign turned positive because it is negative times negative)

5/-5

Simplify: 5/-5 = -1 = -x

The slope of this line is -x

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Step-by-step explanation:

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1.601 rounded to the nearest half is 1 1/2.

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2 years ago

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3 years ago

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3 years ago

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3 years ago

In ΔABC, if m ∠A = m∠C, m∠B = ß (where ß is an acute angle), and BC = x, which expression gives the length of b, the side opposi

chubhunter [2.5K]

Answer:

The length of b is $\sqrt{2x^2(1-cos\beta)}$ .

Step by step explanation:

Given information: In ΔABC, ∠A =∠C, ∠B = ß (where ß is an acute angle), and BC = x.

Since two angles are same therefore triangle ABC is an isosceles triangle and side AB and BC are congruent.

$AB=BC=x$

According to Law of cosine

$b^2=a^2+c^2-2ac\cos B$

$b^2=x^2+x^2-2(x)(x)\cos \beta$

$b^2=2x^2-2x^2\cos \beta$

$b^2=2x^2(1-\cos \beta)$

$\sqrt{2x^2(1-cos\beta)}$

Therefore the length of b is $\sqrt{2x^2(1-cos\beta)}$ .

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3 years ago