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3 years ago

5

How many moles of gas sample are 5.0 L container at 373K and 203kPa

1 answer:

Rom4ik [11]3 years ago

6 0

For the purpose we will here use t<span>he ideal gas law:

p</span>×V=n×R×<span>T

V= </span><span>5.0 L

T= </span><span>373K

p= </span><span>203kPa
</span><span>
R is </span> universal gas constant, and its value is 8.314 J/mol×<span>K
</span>
Now when we have all necessary date we can calculate the number of moles:

n=p×V/R×T

n= 203 x 5 / 8.314 x 373 = 0.33 mole

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3 years ago

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3 years ago