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True [87]
3 years ago
5

How many moles of gas sample are 5.0 L container at 373K and 203kPa

Chemistry
1 answer:
Rom4ik [11]3 years ago
6 0
For the purpose we will here use t<span>he ideal gas law:

p</span>×V=n×R×<span>T

V= </span><span>5.0 L

T= </span><span>373K

p= </span><span>203kPa
</span><span>
R is </span> universal gas constant, and its value is 8.314 J/mol×<span>K
</span>
Now when we have all necessary date we can calculate the number of moles:

n=p×V/R×T

n= 203 x 5 / 8.314 x 373 = 0.33 mole
 
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Sort the following chemicals for their ability to act as an oxidizer. List from strongest to weakest; 1 being strongest, 6 being
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Answer : If we list the given chemicals according to their increasing oxidising ability then the order will be like this; 1 being the strongest and 6 being the weakest 
1. K > 2. Ca >3. Ni> 4. Cu> 5. Ag> 6.Au

Explanation : Considering the reduction potential of each chemical species it will be easy to identify their oxidising capacity and differentiate accordingly;

More negative the value of reduction potential more is the ability of the chemical species to get oxidised.

Chemicals with their reduction potential is given below.

K has -2.92; Ca has -2.76; Ni has -0.23; Cu has 0.52; Ag has 1.50 and Au has 1.50.


7 0
4 years ago
Read 2 more answers
An ambulance took 2 hours to cover a distance of 10 kilometers. Find its speed.​
bekas [8.4K]

Answer:

5km/hour

Explanation:

2hours = 10km

/2              /2

1 hour = 5km

7 0
3 years ago
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What is the ph of a solution of 1.699 l of 1.25 m hcn, ka = 6.2 x 10-10, and 1.37 moles of nacn?
BlackZzzverrR [31]

The pH of a solution is 9.02.

c(HCN) = 1.25 M; concentration of the cyanide acid

n(NaCN) = 1.37 mol; amount of the salt

V = 1.699 l; volume of the solution

c(NaCN) = 1.37 mol ÷ 1.699 l

c(NaCN) = 0.806 M; concentration of the salt

Ka = 6.2 × 10⁻¹⁰; acid constant

pKa = -logKa

pKa = - log (6.2 × 10⁻¹⁰)

pKa = 9.21

Henderson–Hasselbalch equation for the buffer solution:

pH = pKa + log(cs/ck)

pH = pKa + log(cs/ck)

pH = 9.21 + log (0.806M/1.25M)

pH = 9.21 - 0.19

pH = 9.02; potential of hydrogen

More about buffer: brainly.com/question/4177791

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8 0
1 year ago
There are seven major levels of classification. Kingdom and Phylum are just two of the levels. Which of the following are also m
kumpel [21]
A) The class and C) Family would be the only accurate option. Here are the levels from largest to smallest: <span>kingdom, phylum, class, order, family, genus and species.</span>
7 0
3 years ago
A sample of seawater weighs 250 g and has a volume of 173 ml. What is the density of seawater?
kari74 [83]

Answer:

<h2>The answer is 1.45 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of seawater = 250 g

volume = 173 mL

It's density is

density =  \frac{250}{173}  \\  = 1.4450867052...

We have the final answer as

<h3>1.45 g/mL</h3>

Hope this helps you

8 0
3 years ago
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