Answer:
(Fe(OH)2 + Na2SO4
Explanation:
Iron (II) hydroxide precipitate. Iron (II) hydroxide precipitate (Fe(OH)2) formed by adding few drops of a 1M solution of sodium hydroxide (NaOH) to 0.2 M solution ferrous sulfate (FeSO4). The reaction is FeSO4 + NaOH -> Fe(OH)2 + Na2SO4. This is an example of a double replacement reaction. Pure iron (II) hydroxide is white, however even trace amounts of oxygen make it greenish.
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Answer:
+6
Explanation:
We are given;
We are required to determine the oxidation number of S in the compound.
We need to know that;
- The total oxidation number of this compound is Zero
- Oxidation number of Ba metal is +2
- Oxidation number of Oxygen atom is -2
- There is 1 atom of Ba, 1 atom of S and 4 atoms of O in the compound.
Therefore; assuming oxidation number of S is x
Then, (1× 2) + (1 × x) + ( 4 ×(-2)) = 0
2 + x - 8 = 0
x = 6 or +6
Thus oxidation number of Sulfur in BaSO₄ is +6.
Answer:
either i have no brain or im over thinking it
Explanation:
