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2 years ago

How many moles of gas sample are 5.0 L container at 373K and 203kPa

1 answer:

6 0

For the purpose we will here use the ideal gas law:

p×V=n×R×T

V= 5.0 L

T= 373K

p= 203kPa

R is universal gas constant, and its value is 8.314 J/mol×K

Now when we have all necessary date we can calculate the number of moles:

n=p×V/R×T

n= 203 x 5 / 8.314 x 373 = 0.33 mole

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50.0 g of NaNO3 are dissolved into enough water to make 250 mL of solution. What is the molarity of this solution?

d1i1m1o1n [39]

Answer:

2.35 M

Explanation:

Molarity is mol/L of solution. We have to convert the g to mol and the mL to L. G to mol uses the molar mass of the compound. The molar mass of NaNO₃ is 85.00g/mol.

$50.0gNaNO3*\frac{1molNaNO3}{85.00gNaNO3} = 0.588molNaNO3$

Then you have to convert mL to L.

$250mL*\frac{1L}{1000mL} = 0.250L$

Now divide the mol by the L.

$\frac{0.588mol NaNO3}{0.250L} = 2.352 M$

Round to the smallest number of significant figures = 2.35M

7 0

2 years ago

how many molecule of carbon dioxide are needed to react with excess iron oxide to produce 11.6 g of iron

lesya692 [45]

Answer:

0.16 moles of Carbon

Explanation:

The balanced reaction equation:

$2Fe_{2}O_{3}$ + $3C$ → $4Fe$ + $3CO_{2}$ ↑

The mole ratio of Carbon to Iron is 3 : 4 (since Fe2O3 is in excess)

i.e 3 moles of C produces 4 moles of Fe.

If 1 mole of Fe - 55.8g of Fe

? moles - 11.6g of Fe

= $\frac{11.6}{55.8}$ = 0.208 moles

But 3 moles of C - 4 moles of Fe

? moles of C - 0.208 moles of Fe

= $\frac{3 *0.208}{4}$ = 0.16 moles of carbon.

I hope this explanation was clear and useful.

5 0

2 years ago

How many kilojoules are needed to convert 77.5 grams of ice at -8.00°C to water at 95.0°C?

Over [174]

Q=mcθ
m= 0.0775 kg
c= 4184 J·kg−1·K−1.
θ= T(final) - T(initial), 95-(-8)

Q=33398.78 J so kJ divide 1000

= 33.39878 kJ

7 0

1 year ago

Name the type of bond between atoms in ammonia molecule. Give a reason for your answer

Likurg_2 [28]

Answer:

Covalent bonds are formed when electrons are shared between elements that are nonmetals. The ammonium ion, NH+4 , would have covalent bonds because both nitrogen and hydrogen are nonmetals. ... The rest of the bonds all contain electrons from both hydrogen and nitrogen, so they would be considered ordinary covalent bonds.

6 0

2 years ago

Read 2 more answers

How many moles are in 36 g of Beryllium (Be)?

Katarina [22]

Answer is B 4 moles .

6 0

2 years ago