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lana [24]
2 years ago
13

Which of the following are found inside the nucleus? Select all that apply.

Chemistry
1 answer:
katrin [286]2 years ago
3 0
Neutron is the answer. you’re welcome bro
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Susie cooked sausages on a barbecue. Fat and water in the sausages changed state. which two changes of state occur during this p
padilas [110]

Answer:

The options a and b are correct

Explanation:

This options provided to the question are the answers to the question. But for clarification. When the fat melts, the change of state that occurs here is from solid to liquid (which is called melting) while the change of state that occurs when the water evaporated is from liquid to gas (which is called evaporation).

5 0
2 years ago
Acids and bases can neutralize each other in double displacement reactions. For example, if hydrogen chloride (a strong acid, HC
scoray [572]

Answer:

The answer to your question is    HCl  +  NaOH   ⇒   NaCl  +  H₂O

Explanation:

Data

Double displacement reaction

Balanced chemical reaction

               HCl  +  NaOH   ⇒   NaCl  +  H₂O

           Reactants           Elements                Products

                 1                  Chlorine (Cl)                    1

                 1                   Sodium (Na)                   1

                 2                 Hydrogen (H)                  2

                 1                   Oxygen (0)                      1

As we can see, the reaction is balanced and the coefficients of all reactants and products are 1, but the number is not written in a balanced reaction.

8 0
3 years ago
Determine the equilibrium constant, Keq, at 25°C for the reaction
adelina 88 [10]

Explanation:

The given chemical reaction is:

2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

E^ocell=oxidation potential of anode + reduction potential of cathode\\

The relation between Eo cell and Keq is shown below:

deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

E^ocell= (-1.07+0.53)V\\=-0.54V

F=96485 C/mol

n=2 mol

R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

Answer:

Keq=6.13x10^33

3 0
3 years ago
How many molecules of Oxygen are consumed if 24 molecules of Carbon Dioxide are produced?
Nat2105 [25]

Answer:

Explanation:

C + O2 → CO2

Mole of C = 24 g/(12 g/mole)

Mole of C = 2 mole

Mole of molecular O2 = 74 g/(32 g/mole)

Mole of molecular O2 = 2.3125 mole

Since mole of C < mole of O2, then C being the limiting reagent.

From the reaction, it shows that mole ratio between C and O2 = 1 : 1.

So, 2 moles of C will stoichiometrically react with 2 moles of O2 to generate 2 moles of CO2.

Avogadro's law states that :"equal volumes of all gases, at the same temperature and pressure, have the same number of molecules i.e. 6.02 x 10^23 molecules/mole.

Therefore, 2 moles of CO2 contain 2 moles x 6.02 x 10^23 molecules/mole = 1.204 x 10^24 molecules of CO2 is formed.

6 0
3 years ago
When you are balancing chemical reactions ('equations'), what must you never touch?
timofeeve [1]

You should never touch the subscripts, as that will change the composition. Hope I helped!

8 0
3 years ago
Read 2 more answers
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