The distance, s = 40t₁ where t₁ is the time to complete the outward journey.
The same distance = vt₂ where t₂ is the time to complete the return journey at speed v.
For the whole journey, 2s=60(t₁+t₂). Therefore s=30(t₁+t₂)=40t₁=vt₂.
30t₁+30t₂=40t₁, 10t₁=30t₂, t₁=3t₂, so s=120t₂=vt₂ and v=120kph.
Answer:


Step-by-step explanation:
Given [Missing from the question]
Equation:

Interval:


Required
Determine the values of 
The given expression:

... shows that the value of
is positive
The cosine of an angle has positive values in the first and the fourth quadrants.
So, we have:

Take arccos of both sides

--- In the first quadrant
In the fourth quadrant, the value is:


So, the values of
in degrees are:

Convert to radians (Multiply both angles by
)
So, we have:




Answer:
Subtract 4
Step-by-step explanation:
-3 - 4 = -7
-7 - 4 = -11
-11 - 4 = -15
ANSWER: 3x^2 + 6
4x^2 + 1 - (x^2 - 5) = 3x^2 + 6
Continuous, because its the area.
Hope this helps...