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3 years ago

Is 4 a factor of 28 in math

2 answers:

algol133 years ago

7 0

Yes and if you want to know you only need o find is the numbers has something in common with the other

Can u mark me as brainliest plz

aalyn [17]3 years ago

4 0

True, because:

4*7=28

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Four cups are placed upturned on the counter. each cup has the same number of sweets and a declaration about the number of sweet

Mumz [18]

Answer:

6? i hope this helps some! :)

Step-by-step explanation:

each has 6 in between the number

5 or 6 p there is a possibility of there being 6

7 or 8 there is at least 6 in this cup

6 or 7 there is at least 6 in this cup

7 or 5 there is a possibility of there being 6

4 0

3 years ago

1. Which of the following measurements could be the three side lengths of a right triangle? a. 4 cm, 5 cm, 9 cm b. 12 cm, 20 cm,

HACTEHA [7]

Answer:

b and c

Step-by-step explanation:

The Triangle Inequality Theorem lets us know that the sum of the two shortest sides of the triangle must be greater than the third side of the triangle.

In both A and D, the sum of the shortest two sides are equal to, not greater than the third side, so they will not form a triangle.

In B, 12+20 is 32, which is greater than 25. And in C, 18+24 is 42, which is greater than 30, so they both will form a triangle.

8 0

3 years ago

Find the indicated probability.

natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

Recall:

Binomial Distribution --> $P(k)={n\choose k}p^kq^{n-k}$
$P(k)$ denotes the probability of $k$ successes in $n$ independent trials
$p^k$ denotes the probability of success on each of $k$ trials
$q^{n-k}$ denotes the probability of failure on the remaining $n-k$ trials
${n\choose k}=\frac{n!}{(n-k)!k!}$ denotes all possible ways to choose $k$ things out of $n$ things

Given:

$n=10$
$k=4$
$p^k=0.53^4$
$q^{n-k}=(1-0.53)^{10-4}=0.47^6$
${n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210$

Calculate:

$P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179$

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

7 0

2 years ago

A total of 243 tickets were sold for the school play. They were either adult tickets or student tickets. The number of student t

alina1380 [7]

Answer:

81 adult tickets

Step-by-step explanation:

Step 1:

Set up a system of equations

Since the adult tickets and student tickets add to 243, we can do

$a+s=243$

and the student tickets sold were 2x the adult tickets, we can do

$s=2a$

We can replace s in the first equation adding to 243 with 2a

$a+s(2a)=243\\3a=243\\$

Step 2:

Solve for a. We can divide both sides by 3.

$a=81$

Therefore, there were 81 adult tickets sold.

Step 3:

We can check our work! Since we learned earlier the student tickets are 2x adult tickets, we can multiply 81 by 2 and add that to 81 to see if it equals 243!

$s=2a\\s=2(81)\\s=162$