Answer:
In radical from 169/50 , 177/200
Step-by-step explanation:
Given:

Find:
Value of 
Computation:
Using quadratic formula:

Value of
3.38 , 0.885
In radical from 169/50 , 177/200
Answer:
II. The sum of the residuals is always 0.
Step-by-step explanation:
A least squares regression line is a standard technique in regression analysis used to make the vertical distance obtained from the data points running to the regression line to become very minimal or as small as possible.
For any least-squares regression line, the sum of the residuals is always zero.
Basically, residuals are used to measure or determine whether or not the line of regression is a good fit or match for the data by subtracting the difference between them i.e the predicted y value and the actual y value, for the x value respectively.
Hence, the statement about residuals which is true for the least-squares regression line is that the sum of the residuals is always zero (0).
Because the discriminant is less than zero, there are no real solutions in the equation.
Answer: x=13
Step-by-step explanation: