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Marina CMI [18]

2 years ago

13

The dot plots show the numbers of children’s books purchased by customers at two different bookstores on one day.

1 answer:

ololo11 [35]2 years ago

3 0

Answer:

A

Step-by-step explanation:

since mean is the most annoying to calculate I went through and did everything else, the range is the same as both charts go 0-6. The median is is the middle number which means store 1 has a higher number of 3' s but our option says store 2 is greater and B is the mode, the number that shows up the most.

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solve the equation below for y. 8x − 2y = 24 a. y = 4x − 12 b. y = 12 − 4x c. y = 8x − 24 d. y = 4x − 8

Feliz [49]

the answer is a. 4x-12

7 0

3 years ago

Which number is irrational

alina1380 [7]

For this case, we have by definition, that an irrational number is a number that can not be expressed as a fraction $\frac {a} {b}$ , where a and b are integers and b is nonzero.

Some examples are:

$\sqrt {2}, \sqrt {3}, e, \pi.$

So, that the answer is $\pi.$

Answer:

Option C

4 0

3 years ago

What is the simplest form for 4/3?

shutvik [7]

4/3 in simplest form is 4/3 but in decimal form it would be 1.33333

hope this helped, please mark brainilest :)

3 0

3 years ago

Read 2 more answers

Use the identity (x2+y2)2=(x2−y2)2+(2xy)2 to determine the sum of the squares of two numbers if the difference of the squares of

fomenos

Answer:

The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>

Step-by-step explanation:

Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.

We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Since, given the difference of the squares of the numbers is 5 that is $(x^2-y^2)^2=5$

And the product of the numbers is 6 that is $xy=6$

Using identity, we have,

$(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2$

Substitute, we have,

$(x^2+y^2)^2=(5)^2+(2(6))^2$

Simplify, we have,

$(x^2+y^2)^2=25+144$

$(x^2+y^2)^2=169$

Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169

5 0

3 years ago

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F(x) = 2x^2 – 5x; find f(3)

Nookie1986 [14]

Answer:

f(3) = 3

Step-by-step explanation:

f(x) = 2x^2 – 5x

Let x = 3

f(3) = 2(3)^2 - 5(3)

= 2*9 -15

= 18-15

=3

4 0

3 years ago

Read 2 more answers