Take the derivative of x^2 to get 2x.
Take the derivative of -2xy to get -2y +-2x
(Everytime you take the derivative of y, you write
.
Take the derivative of -3y^2 to get -6y
.
Get the terms with
on one side to get:
-2x
- 6y
= 2x - 2y
Take out the common factor of
to get:
[-2x - 6y] = 2x - 2y
Divide by -2x - 6y to get:
=
Answer: The answer is A
Step-by-step explanation:
-5x+y=-3. (1) isolate y 1.First isolate a variable.( I isolated y because it was already isolated)
3x-8y=24. (2). 2.Then substitute that into the other equation
—————. 3. Then solve for X
Sub y=5x-3 into (2). 4. Then substitute X into one of the equations
5. Then solve for Y and ta-da you find the answer.
3x-8(5x-3)=24.
3x-40x+24=24. Hope this helped! :)
3x-40x=24-24
-37x=0
X=0
——————
Sub x=0 into (1)
-5(0)+y=-3
Y=-3
.: (0,-3)
Answer:
15400√5−45π
Step-by-step explanation:
Rewrite the expression, pull the terms out from the radical, cancel the common factors, and multiply.
Can salvage 15c+ -15c is 0 + 8 is still 0