Answer:
50
Step-by-step explanation:
The length of the midsegment is half the length of the base segment, so you have ...
... 2(6x +2) = 2x +84
... 10x = 80 . . . . . . . . . simplify, subtract 2x+4
... x = 8
The length of the midsegment is 6·8+2 = 50.
There would be 3 and 1/2 pounds left.
2/3 x 2 = 4/6
5/6
5/6 + 4/6 = 6/6 (1) and 3/6 (1/2)
Use ax^2 + bx + c = 0
ac = -8
b = 2
The factors are 4 and -2.
Plug them into the equation:
x^2 + 4x - 2x - 8
Then factorise it:
x ( x + 4) - 2 (x + 4)
so m = 4
(x + 4)^2
You will need three roots for this, so we have
Let x = -30, -10 and +20
So the factors will be (x+30)(x+10)(x-20)
The divide it to 100, this will help bring the peak up and down
So the polynomial function R(x) will become
1/100 * (x+30)(x+10)(x-20)
R(x) = 1/100 * (x+30)(x+10)(x-20)
Finding the X-intercept:
Let R(x) = 0 and solve for x.
1/100 * (x+30)(x+10)(x-20) = 0
x = -30, -10, 20 are the x-intercepts.
