Answer:
p = -5 (only)
Step-by-step explanation:
It looks like we want to count solutions for ...
(1.5p -1) = (1 +1.1p) -4
0.4p = -2
p = -2/0.4 = -5
For p having a value of -5, the binomial (1.5p -1) = -8.5 will be smaller than the value of (1 +1.1p) = -4.5 by 4.
Answer:in what grade are the students in
Step-by-step explanation:
Based on the random sample of beach lengths taken, the probability of a randomly selected beach having a length of 12 miles is C. 0.
<h3>What is the probability that a beach is 12 miles in length?</h3>
Beach length is considered a continuous variable which takes a numerically positive form because it can have any one of infinite possible values.
As a result, there is no possibility that a beach chosen at random will have a given length of 12 miles which means that the probability is 0.
In conclusion, the probability that a selected beach has a length of 12 miles is 0.
Find out more on continuous variables at brainly.com/question/27761372
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Answer: 0.0548
Step-by-step explanation:
Given, A research study investigated differences between male and female students. Based on the study results, we can assume the population mean and standard deviation for the GPA of male students are µ = 3.5 and σ = 0.05.
Let 
represents the sample mean GPA for each student.
Then, the probability that the random sample of 100 male students has a mean GPA greater than 3.42:
![P(\overline{X}>3.42)=P(\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}>\dfrac{3.42-3.5}{\dfrac{0.5}{\sqrt{100}}})\\\\=P(Z>\dfrac{-0.08}{\dfrac{0.5}{10}})\ \ \ [Z=\dfrac{\overline{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}]\\\\=P(Z>1.6)\\\\=1-P(Z](https://tex.z-dn.net/?f=P%28%5Coverline%7BX%7D%3E3.42%29%3DP%28%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%3E%5Cdfrac%7B3.42-3.5%7D%7B%5Cdfrac%7B0.5%7D%7B%5Csqrt%7B100%7D%7D%7D%29%5C%5C%5C%5C%3DP%28Z%3E%5Cdfrac%7B-0.08%7D%7B%5Cdfrac%7B0.5%7D%7B10%7D%7D%29%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7B%5Coverline%7BX%7D-%5Cmu%7D%7B%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D%5D%5C%5C%5C%5C%3DP%28Z%3E1.6%29%5C%5C%5C%5C%3D1-P%28Z%3C1.6%29%5C%5C%5C%5C%3D1-0.9452%3D0.0548)
hence, the required probability is 0.0548.
