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3 years ago

9

If the measures of two sides of a triangle are 5 yards and 9 yards, what is the least possible measure of the third side if the

measure is an integer?

1 answer:

natali 33 [55]3 years ago

5 0

Answer:

5

Step-by-step explanation:

if it was any shorter the triangle would turn into a line

9-5=4 but there would be no area so you add +1

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A cube has side length a. The side lengths are decreased to 20% of their original size. Write an expression in simplest form for

sergiy2304 [10]

Volume of the original cube is a³ .
That's (a · a · a) .

If you decrease the sides to 20% of their original size,
then the new volume is (0.2a · 0.2a × 0.2a).

That's 0.008a³ or (0.2a)³ .

Take your choice. I can't decide which one is simpler.

8 0

3 years ago

Read 2 more answers

The length of a diagonal of a square is 7.5 mm. Find the area of the square.

dexar [7]

By Pythagoreans' theorem,

7.5² = l² × b²
56.25 = l² × b²

Since l = b
56.25 ÷ 2
= l²/b²
= 28.125 mm

∴ l = √28.125
= 5.3033 mm

Area of square
= √28.125 × √28.125
= 28.125 mm²
≈ 28.1 mm² (3s.f.)

7 0

3 years ago

Find the volume of the solid generated by revolving the region bounded by

Rama09 [41]

Answer:

$V =\dfrac{25\pi}{\sqrt{2}}$

Step-by-step explanation:

given,

y=5√sinx

Volume of the solid by revolving

$V = \int_a^b(\pi y^2)dx$

a and b are the limits of the integrals

now,

$V = \int_a^b(\pi (5\sqrt{sinx})^2)dx$

$V =25\pi \int_{\pi/4}^{\pi/2}sinxdx$

$\int sin x = - cos x$

$V =25\pi [-cos x]_{\pi/4}^{\pi/2}$

$V =25\pi [-cos (\pi/2)+cos(\pi/4)]$

$V =25\pi [0+\dfrac{1}{\sqrt{2}}]$

$V =\dfrac{25\pi}{\sqrt{2}}$

volume of the solid generated is equal to $V =\dfrac{25\pi}{\sqrt{2}}$

4 0

3 years ago

What set of transformations is performed on triangle RST to form triangle R’S’T’?

ra1l [238]

Answer:

D. A translation 2 units down followed by a 270-degree counterclockwise rotation about the origin

Step-by-step explanation:

The given triangle has vertices at R(3,4), S(1,1), and T(5,1)

Translating the the vertices down by 2 units, we apply the rule;

$(x,y)\to (x,y-2)$

$\implies (3,4)\to (3,2)$

$\implies (1,1)\to (1,-1)$

$\implies (5,1)\to (5,-1)$

Rotating the resulting vertices through an angle 270 degrees counterclockwise, we apply the rule:

$(x,y)\to (x,-y)$

$\implies (3,2)\to R'(2,-3)$

$\implies (1,-1)\to S'(-1,-1)$

$\implies (5,-1)\to T'(-1,-5)$

Therefore the correct choice is D.

4 0

3 years ago

18 - 2 x (4 + 3)<br> Pls help

Andreas93 [3]

Answer: 4

Step-by-step explanation:

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2 years ago