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2 years ago

A system of equations has no solution. If y = 8x + 7 is one of the equations, which could be the other equation?

Mathematics

2 answers:

Cloud [144]2 years ago

4 0

Step-by-step explanation:

the answer is 2y=16x+14

cupoosta [38]2 years ago

4 0

Answer:

2y=16x+14

Step-by-step explanation:

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2 years ago

Factor p^2−6−q·(p^2−6)^2

Olenka [21]

Answer:

(p^2−6) (1-q(p^2-6))

Step-by-step explanation:

p^2−6−q·(p^2−6)^2

Put parentheses around the P^2-6 at the beginning of the expression

(p^2-6) -q (p^2−6)^2

Factor out (p^2−6)

(p^2−6) (1-q(p^2-6))

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2 years ago

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Lol but how do i do this??

Pepsi [2]

Answer:

Y=x+12

Step-by-step explanation:

Not pretty sure XD but .-.

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3 years ago

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When obtaining a confidence interval for a population mean in the case of a finite population of size N and a sample size n whic

Elanso [62]

Answer:

95% Confidence interval for the mean

$142.8 \leq\mu\leq158.4$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean of a finite population.

The error is multiplied by the following finite population correction factor:

$cf=\sqrt{\frac{N-n}{N-1} }$

The standard deviation can be estimated as

$\sigma=\frac{s}{\sqrt{n}} \sqrt{\frac{N-n}{N-1} } =\frac{24.4}{\sqrt{32} }* \sqrt{\frac{200-32}{200-1} }=3.963$

The 95% confidence interval has a z value of 1.96, so it becomes:

$M-z*\sigma_c\leq\mu\leq M+z*\sigma_c\\\\150.6-1.96*3.963\leq\mu\leq 150.6+1.96*3.963\\\\ 142.8 \leq\mu\leq 158.4$

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3 years ago

Which one is the answer

docker41 [41]

Answer:

Step-by-step explanation:

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2 years ago

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