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3 years ago

Please help me guys ill mark you as a brilliant

Mathematics

1 answer:

Tomtit [17]3 years ago

4 0

Answer:

so the answer is ,,5". hope this helped! Have a nice day.

Step-by-step explanation:

45:9=5

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Use the substitution method to solve the system of equations. Choose the correct ordered pair.

zubka84 [21]

Answer:

A) (3,14)

Step-by-step explanation:

6x - 4 =7x - 7

subtract 6x from both sides

-4 = x -7

add 7 to both sides

3= x

now that we know the value of x, plug it into either equation to get y=14

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3 years ago

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What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?

Deffense [45]

So you have a right angle triangle. You need to use trig for this, as you have two values you can figure out a third.

You know that you have

90 deg. angle
19 deg. angle
Therefor you have 71 deg. angle

sin19 = x/15
15sin19 = x
x = 2.2

Now do Pythagoras c^2-b^2=a^2

a = 14.8

So the sides are 2.2 and 14.8 units long. (If these numbers are wrong tell me and I'll edit answer)

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3 years ago

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Find the P-value for the indicated hypothesis test. An airline claims that the no-show rate for passengers booked on its flights

trapecia [35]

Answer:

$p_v =P(z$

B. 0.2061

Step-by-step explanation:

1) Data given and notation

n=380 represent the random sample taken

X=19 represent the no-shows in the sample

$\hat p=\frac{19}{380}=0.05$ estimated proportion of no-shows in the sample

$p_o=0.06$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the no-show rate for passengers booked on its flights is less than 6%:

Null hypothesis: $p\geq 0.06$

Alternative hypothesis: $p < 0.06$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.05-0.06}{\sqrt{\frac{0.06(1-0.06)}{380}}}=-0.8208$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a one left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level for example $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of no-show rate for passengers booked on the company flights is nor significantly less than 0.06 or 6%.