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harina [27]
3 years ago
13

The graph shows the prices of different numbers of bushels of corn at a store in the current year. The table shows the prices of

different numbers of bushels of corn at the same store in the previous year.
A graph shows Number of Bushels on x-axis and Price of Corn in dollars on y-axis. The x-axis scale is shown from 0 to 21 at increments of 3, and the y-axis scale is shown from 0 to 168 at increments of 24. A straight line joins the ordered pairs 3, 24 and 6, 48 and 9, 72 and 12, 96 and 15, 120 and 18, 144.


Previous Year
Number of Bushels
Price of Corn (dollars)
3
21
6
42
9
63
12
84


Part A: Describe in words how you can find the rate of change of a bushel of corn in the current year, and find the value. (5 points)
Part B: How many dollars more is the price of a bushel of corn in the current year than the price of a bushel of corn in the previous year? Show your work. (5 points)

Mathematics
2 answers:
nevsk [136]3 years ago
7 0

Answer: hift rate of the previous year's maize bushel = (20-10)/(4 – 2) = = 10/2 = 5 Graph 2, 14, 4, 28, 6, 42 and 8, 56 and 10, 70, and 12, 84 Current year This year's rate of adjustment of the maize bushel, = (28 - 14)/(4 -2) = 14/2 = 7 7 - 5= 2 USD is more than the price of the maize bushel in the current year than the pre-year price of the maize bushel.

Step-by-step explanation:

Sauron [17]3 years ago
3 0

Given: in the previous year, the table shows the prices of various amount of maize bushels in the same store.

A diagram displays the number of x-axis bussels and the price of maize in y axis dollars for 2012.

Search: The rate of change in this year's maize bushel, Part B: How many dollars is the present year's price of a maize bushel higher than in the previous year's maize bushel

Finding:

Earlier Year Panel

Bushel Number Corn prices

Shift rate of the previous year's maize bushel = (20-10)/(4 – 2) = = 10/2 = 5 Graph 2, 14, 4, 28, 6, 42 and 8, 56 and 10, 70, and 12, 84 Current year This year's rate of adjustment of the maize bushel, = (28 - 14)/(4 -2) = 14/2 = 7 7 - 5= 2 USD is more than the price of the maize bushel in the current year than the pre-year price of the maize bushel.

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A bag contains 2 white marbles and 7 purple marbles. Two marbles are drawn at random. One marble is drawn and not replaced. Then
Masja [62]
A.
\frac{7purple}{9total} *  \frac{2white}{8total}  \\  \frac{14}{72}  \\ =0.194
The denominator of the second number goes down one because you aren't replacing the initial marble pulled, making the amount of marbles in the bag go down, but not affecting the white count because you pulled a purple marble.
b.
\frac{2white}{9total} *  \frac{1white}{8total}  \\  \frac{2}{72}  \\ =0.278
The same can be said about the denominator for this problem, but not the numerator. The numerator must go down one number as well, because you already chose one white marble, taking one of the white marbles out of the bag, leaving you with one solitary, white marble.
c.
Chance of selecting two purple marbles:
<u />\frac{7purple}{9total} *  \frac{6purple}{8total}  \\  \frac{42}{72}  \\ =0.583
Chance of selecting two white marbles:
\frac{2white}{9total} * \frac{1white}{8total} \\ \frac{2}{72} \\ =0.278
<u>Chance of selecting two purple</u> vs. <em>Chance of Selecting 2 white:</em>
<u>0.583</u>><em>0.278</em>.
It is more likely to select 2 purple marbles.

Hope this helps!
6 0
3 years ago
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The quotient of 9 and a number less 4
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Answer:

ead the excerpt from "The Most Dangerous Game,” by Richard Connell.

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3 years ago
Write a rule for the nth term of the arithmetic sequence:<br><br> a11= 50, d = 7
ivolga24 [154]

Answer:

Required rule for n^{th} is a_{n}=7n-27.

Step-by-step explanation:

Given that,

a_{11} = 50,\  \  d=7

From the question: we have to write the n^{th} term of Arithmetic sequence.

Arithmetic Sequence or Arithmetic progression (A.P) : It is a sequence which possess that difference between of two successive sequence is always constant.

                a_{1} ,a_{2},a_{3},a_{4}.....................a_{n-1},a_{n}

                                        where, a_{1} is the first term of A.P

                                                     d is the common difference.

                                                     a_{n} is the last term or general term.

The above sequence to be in A.P then their common difference should be equal.

          d=a_{2}-a_{1} =a_{3}-a_{2}=a_{4} -a_{3} ..........................a_{n}-a_{n-1}

Now, Formula of General Term is a_{n}=a+(n-1)d

So,                                                    a_{11}= a+(11-1)d\\        a_{11} = a+10d

 Substituting the value of   a_{11} = 50,\  \  d=7 we get,

                                                         50=a+10\times7\\50=a+70\\a=-20

Then General term (a_{n}) of given data is

                                                         a_{n}=-20+(n-1)7\\a_{n}=-20+7n-7\\a_{n}=7n-27

Therefore, Required rule for n^{th} is a_{n}=7n-27.

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3 years ago
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insens350 [35]

Answer:

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Answer:

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Step-by-step explanation:

Value after t years = initial value ( 1 - r )^t

Where,

Value after t years= $5000

Initial value = $22,400

r= depreciation rate = 11%

t= length of time (years)

Value after t years = initial value ( 1 - r )^t

5000 = 22,400 ( 1 - 0.11)^t

5000 = 22,400(0.89)^t

Divide both sides by 22,400

(0.89)^t = 5000 / 22,400

(0.89)^t = 0.2232

Take the log of both sides

t log 0.89 = log 0.2232

t= log 0.2232 / log 0.89

= -0.6513 / -0.0506

= 12.87

t= 12.9 years

5 0
3 years ago
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