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3 years ago

How many millimeters are in 3.4 liters?

Mathematics

2 answers:

Diano4ka-milaya [45]3 years ago

7 0

Answer:

3400 milliliters

Step-by-step explanation:

Over [174]3 years ago

4 0

3400
I think there’s a 1000ml in a litre so just multiply 3.4 by 1000

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What number needs to be subtracted from both sides of the equation 40 = 25 + x in order to isolate the variable and solve for x?

SOVA2 [1]

Answer:

x = 15

Step-by-step explanation:

As given, the equation 40 = 25 + x

As on the R.H.S of the equation, there is one constant and a variable x

As to isolate the variable we have to subtract the same constant so that that constant gives 0.

As we have the constant value 25

So, subtract 25 from both side of the equation, we get

40 - 25 = 25 + x - 25

⇒15 = x

∴ we get

x = 15

3 0

3 years ago

A speed of 220 feet per minute is equal to how many miles per hour

garik1379 [7]

Answer: 2.5 miles per hour

Step-by-step explanation:

this problem is all about conversions

220 ft per minute

first get it to hours, since there is 60 minute in an hour multiply by a factor of 60

220 ft per minute becomes 13200 ft per hour

then you need to covert from ft to mi, there are 5280 ft in 1 mi so divide by 5280

13200 ft per hour becomes 2.5 miles per hour

3 0

3 years ago

PLZ HEEEEEEEELPPPPPPPP!!!!!!!!!

Elena L [17]

Y= ∛(-x) - 3
for x = -8 → y = ∛-(-8) - 3 ↔ y = 2-3 ↔y = -1
for x= 8 → y= ∛(-8) - 3 ↔ y = -2 -3 ↔ y = -5
Then - 5≤ y≤ - 1
hence the range of y is {y|-5≤y≤-1}

5 0

3 years ago

Consider the sequence defined recursively by do = 0, an = an-1 + 3n – 1. a) Write out the first 5 terms of this sequence,

creativ13 [48]

Answer:

The first 5 terms of the sequence is 2,7,15,26,40.

Step-by-step explanation:

Given : Consider the sequence defined recursively by $a_0=0$ $a_n=a_{n-1}+3n-1$

To find : Write out the first 5 terms of this sequence ?

Solution :

$a_n=a_{n-1}+3n-1$ and $a_0=0$

The first five terms in the sequence is at n=1,2,3,4,5

For n=1,

$a_1=a_{1-1}+3(1)-1$

$a_1=a_{0}+3-1$

$a_1=0+2$

$a_1=2$

For n=2,

$a_2=a_{2-1}+3(2)-1$

$a_2=a_{1}+6-1$

$a_2=2+5$

$a_2=7$

For n=3,

$a_3=a_{3-1}+3(3)-1$

$a_3=a_{2}+9-1$

$a_3=7+8$

$a_3=15$

For n=4,

$a_4=a_{4-1}+3(4)-1$

$a_4=a_{3}+12-1$

$a_4=15+11$

$a_4=26$

For n=5,

$a_5=a_{5-1}+3(5)-1$

$a_5=a_{4}+15-1$

$a_5=26+14$

$a_5=40$

The first 5 terms of the sequence is 2,7,15,26,40.

5 0

3 years ago

Choose the domain for which each function is defined

klemol [59]

Answer:

Part 1) $f(x)=\frac{x+4}{x}$ -----> $x\neq 0$

Part 2) $f(x)=\frac{x}{x+4}$ ----> $x\neq -4$

Part 3) $f(x)=x(x+4)$ ----> All real numbers

Part 4) $f(x)=\frac{4}{x^2+8x+16}$ ----> $x\neq -4$

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

$f(x)=\frac{x+4}{x}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=0 the function is not defined

therefore

The domain is

$x\neq 0$

Part 2) we have

$f(x)=\frac{x}{x+4}$

we know that

In a quotient the denominator cannot be equal to zero

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

Part 3) we have

$f(x)=x(x+4)$

Applying the distributive property

$f*(x)=x^2+4x$

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

$f(x)=\frac{4}{x^2+8x+16}$

we know that

In a quotient the denominator cannot be equal to zero

Equate the denominator to zero

$x^2+8x+16=0$

Remember that

$x^2+8x+16=(x+4)^2$

( $x+4)^2=0$

The solution is x=-4

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

6 0

3 years ago