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olga nikolaevna [1]
3 years ago
8

Shane bicycled 4 and 1/2 miles on Monday, 4 miles on Tuesday and 5 and

Mathematics
1 answer:
solniwko [45]3 years ago
4 0
4.5 + 4 + 5.25 = 13.75 miles in total (13 and 3/4)
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1. Is it proportional?
astra-53 [7]

Answer:

Y=5(x) Yes it is porportional.

Step-by-step explanation:

So lets look at the graph.

We first have 1x = 5y

Well, that makes it seem like for each x there are 5 y.

Lets see the other values:

2x = 10y

Divide both sides by 2 tog et x alone:

1x=5y

Again, for each x, there are 5y.

This is true for each one:

3x=15y

=

1x=5y

4x=20y

=

1x=5y

5x=25y

=

1x=5y

and finally:

6x=30y

=

1x=5y.

So yes, this is poroportional.

It can be shown as x=5y, since for a single x, there are 5 y's.

Hope this helps!

5 0
3 years ago
The age at which small breed dogs are fully housebroken follows a Normal distribution with mean ms = 6 months and standard devia
atroni [7]

Answer:

This measure is just 0.17 standard deviations from the mean, so we should not be surprised.

Step-by-step explanation:

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If the z-score is lower than -2, or higher than 2.5, the score of X is considered unusual.

Subtraction of normal variables:

When we subtract normal variables, the mean is the subtraction of the means, while the standard deviation is the square root of the sum of the variances.

Let xS – xL represent the sampling distribution.

Mean s 6, means L 4. So

\mu = 6 - 4 = 2

Standard deviation s is 2.5, for L is 1.5. So

\sigma = \sqrt{2.5^2+1.5^2} = 2.915

Should we be surprised if the sample mean housebroken age for the small breed dogs is at least 2.5 months more than the sample mean housebroken age for the large breed dogs? Explain your answer.

We have to find the z-score for X = 2.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.5 - 2}{2.915}

Z = 0.17

This measure is just 0.17 standard deviations from the mean, so we should not be surprised.

7 0
2 years ago
If f(x)=x+7 and g(x)=<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%20-%2013%7D%20" id="TexFormula1" title=" \frac{
Sergio [31]
Hi,

f(x)=x+7\\&#10;&#10;g(x)= \dfrac{1}{x-13} \\&#10;&#10;(fog)(x)=f(g(x))=f(\dfrac{1}{x-13})=\dfrac{1}{x-13}+7\\&#10;&#10;&#10;
Domain of (fog)(x) is R \ {13} =(-oo 13[ U ]13 +oo)

8 0
3 years ago
5x + 5/4 = x − 3/9 please show work
OLEGan [10]
5x + 5/4 = x - 3/9

5•x + 5/4 = x - 3/9

144x = -57

x = -19
48
≈ -0.395833
5 0
3 years ago
Can anyone help me on #8 ? inverse variation or direct variation? and is #9 right I belive it is
guajiro [1.7K]
#8 is kind of a handful.  But if you just look at what 'y' is doing as 'x' increases ... no matter where you look, 'y' is always decreasing whenever 'x' increases, so that's certainly not a 'direct' relationship.

#9 is correct.  Good work.
7 0
3 years ago
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