The amount of oxygen in the flask through the intake tube illustrates proportions
The flask 99.35% will contain of oxygen after 5L have passed through the intake tube
<h3>How to calculate the percentage of oxygen?</h3>
To do this, we make use of the following representations
- P for the proportion of oxygen
- V for te volume of oxygen
- x for the proportion of oxygen in the flask after 5 L passed through
So. we have the following derivative
dP = dV - P * dV
Divide through by dV
dP/dV = 1 - P
Next, we set up the integral

Integrate both sides

Expand
-ln(|x - 1|) + ln(|0.04 - 1|) = 5
Evaluate the difference
-ln(|x - 1|) + ln(|-0.96|) = 5
Express as a fraction
ln(0.96/|x - 1|) = 5
Express both sides as exponents with a base of 2
e^ln(0.96/|x - 1|) = e^5
Solve for x
x = 1 - 0.96/e^5
Evaluate the difference
x = 0.9935
Express as percentage
x = 99.35%
Hence, the flask 99.35% will contain of oxygen after 5L have passed through the intake tube
Read more about proportions at:
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Answer:
area would be 98.35
Step-by-step explanation:
the area is 98.35 units squared
Answer:
to get what he kept subtract 5 from 18, to get 13 so 13 was kept. the ratio will be kept:sold which is 13:5
i think it might be around 440,112
Answer:
use distributive and combine like terms